CODEWITHSUNDEEP
javavariablestypeschar
danger mouse
danger mouse

Reputation: 1497

Java char variable

The following code within a program allows 90 to be assigned to the variable 'ch'. 'Z' is then printed to the console.

char ch;
ch = 90;
System.out.println(ch);

However, the following code, that lies within a program, does not compile. If the following code requires the input to the ch variable to be a character type, i.e. (char) System.in.read();, then why does the same not apply when 90 is assigned to ch above? Why doesn't it have to be ch = (char) 90?

char ch;
ch = System.in.read();

Upvotes: 0

Views: 829

Answers (2)

Elliott Frisch
Elliott Frisch

Reputation: 201439

Whenever you are dealing with system io you need to ensure that you can handle all valid byte input values. However, you then need a mechanism to indicate that the stream has been exhausted. The javadoc for InputStream.read() (System.in is a global InputStream) says (emphasis added),

Reads the next byte of data from the input stream. The value byte is returned as an int in the range 0 to 255. If no byte is available because the end of the stream has been reached, the value -1 is returned.

If you were to cast -1 to char you would get 65535 because char is unsigned. With byte, it's even worse in that -1 is a valid value. Regardless, you aren't reading char values; you are reading byte(s) encoded as int in the range 0-255 plus -1 to indicate end of stream. If you want char(s) I suggest you look at an InputStreamReader which is described in the javadoc as

An InputStreamReader is a bridge from byte streams to character streams

Upvotes: 0

Eran
Eran

Reputation: 393811

The compiler knows that 90 is a valid value for char. However, System.in.read() can return any int, which may be out of the valid range for chars.

If you change 90 to 90000, the code won't compile:

 char ch;
 ch = 90000;

Upvotes: 2

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