Reputation: 951
Adding the prefix "b" to a string converts it to bytes:
b'example'
But I can't figure out how to do this with a variable. Assuming string = 'example'
, none of these seem to work:
b(string)
b string
b'' + string
Is there a simple way to do this?
Upvotes: 78
Views: 98537
Reputation: 499
You can use the bytes.decode()
method to convert bytes
to string
(using a given encoding):
>>> b'hello'.decode('utf-8')
'hello'
The opposite conversion is str.encode()
to convert a string
to bytes
:
>>> 'hello'.encode('utf-8')
b'hello'
Upvotes: 8
Reputation: 426
I have checked for this for long time and i think the best way to convert a string into a varible is using vars()
vars()['variable name'] = value to assign
vars()['created_variable'] = 1
print(created_variable)
>> 1
Upvotes: 0
Reputation: 518
string = bytes(string, encoding= 'utf-8')
where 'string' is your variable.
Upvotes: 6
Reputation: 9801
# only an example, you can choose a different encoding
bytes('example', encoding='utf-8')
In Python3:
Bytes literals are always prefixed with 'b' or 'B'; they produce an instance of the bytes type instead of the str type. They may only contain ASCII characters; bytes with a numeric value of 128 or greater must be expressed with escapes.
In Python2:
A prefix of 'b' or 'B' is ignored in Python 2; it indicates that the literal should become a bytes literal in Python 3.
More about bytes():
bytes([source[, encoding[, errors]]])
Return a new “bytes” object, which is an immutable sequence of integers in the range 0 <= x < 256. bytes is an immutable version of bytearray – it has the same non-mutating methods and the same indexing and slicing behavior.
Accordingly, constructor arguments are interpreted as for bytearray().
Bytes objects can also be created with literals, see String and Bytes literals.
Upvotes: 68
Reputation: 336468
Use bytes()
:
>>> bytes("hello", encoding="ascii")
b'hello'
Upvotes: 11