CODEWITHSUNDEEP
javaregex
membersound
membersound

Reputation: 86747

How to regex a word that does not contain spaces?

I'd like to regex that a value has no spaces (^[\S]*$) and only contains letters (\w+). But how do I combine these two to one regex?

Expected result should be:

oneword: true
one word: false
1word: false

Upvotes: 1

Views: 16177

Answers (5)

user2030471
user2030471

Reputation:

Use \p{Alpha} which is an alphabetic character:[\p{Lower}\p{Upper}]

With the above your regular expression will be \p{Alpha}+, which matches one or more of alphabetic characters. This ignores digits, underscores, whitespaces etc.

For more info look at section POSIX character classes (US-ASCII only) in this document.

Upvotes: 1

Josh M
Josh M

Reputation: 11937

If you want a non-regex solution, perhaps you could try something like this:

public boolean valid(final String string){
    for(final char c : string.toCharArray())
        if(!Character.isLetterOrDigit(c))
            return false;
    return true;
}

Upvotes: 1

Qtax
Qtax

Reputation: 33908

I guess you may want something like (if the empty string is to be valid):

^[A-Za-z]*$

\w contains digits and _ too, so that would match 1word.

Upvotes: 9

falsetru
falsetru

Reputation: 369064

\w not only match alphabets, but also match digits, underscore(_). To match only alphabets, use:

^[A-Za-z]+$

Upvotes: 1

anubhava
anubhava

Reputation: 785128

For matching letters only this regex would be enough:

^[a-zA-Z]+$
  • \w means letter, digits and underscore

Upvotes: 4

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