CODEWITHSUNDEEP
pythonopencvpython-2.7image-processingpython-imaging-library
Chris Aung
Chris Aung

Reputation: 9492

Python find the coordinates of black square on JPEG image

I have this sample image that has white rectangular box with a single black square in it. (2 blue arrows are just for illustration purpose, they are not part of the image)

enter image description here

Is there anyway to find out how many pixels is the black square away from the left and top boundaries of the image?

If possible, i prefer not to use OpenCV as the rest of the processing were done in PIL and it's probably an overkill if i have to use OpenCV just to do this one operation.

FYI: the image is in JPEG, there will always be only 1 black squre (no multiple squares) in the box.

UPDATE

Based on the answer by karlphillip, i have come up with this piece of code.

from PIL import Image

img = Image.open('test.png').convert('1')
pixels = img.load()

xlist = []
ylist = []
for y in xrange(img.size[1]):
    for x in xrange(img.size[0]):
        if pixels[x, y] == 0:
            xlist.append(x)
            ylist.append(y)

#4 corners of the black square
xleft = min(xlist)
xright = max(xlist)
ytop = min(ylist)
ybot = max(ylist)

Upvotes: 2

Views: 5309

Answers (1)

karlphillip
karlphillip

Reputation: 93410

Based on that link I mentioned, I was able to put together the following pseudocode:

from PIL import Image

img = Image.open('test.png')
pixels = img.load()

for y in xrange(img.size[1]):
    for x in xrange(img.size[0]):
        if pixels[x, y] == (0, 0, 0):
            // black pixel found, add it to a counter variable or something.

This answer demonstrates how to access and test each pixel in the image using PIL.

Upvotes: 1

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