CODEWITHSUNDEEP
pythonruntime-error
user3135491
user3135491

Reputation: 1

Unknown math.sqrt error

When I try this:

import math

g = input("Put your number here: ")

print ("The square root of you number is: " + int(math.sqrt(g)))

And I write 7 as my input per se, I get this error message:

TypeError: a float is required

I would greatly appreciate any solutions and or pointers. Thanks!

Upvotes: 0

Views: 1174

Answers (2)

user2555451
user2555451

Reputation:

You are getting a TypeError because math.sqrt requires a number (either a float or an integer):

>>> import math
>>> math.sqrt(4.0)
2.0
>>> # Integers work too, even though the error message doesn't mention them
>>> math.sqrt(4)
2.0
>>> math.sqrt('4')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: a float is required
>>>

However, input returns a string object in Python 3.x:

>>> x = input()
7
>>> type(x)
<class 'str'>
>>>

This means that g will be a string when you give it to math.sqrt.

To fix the problem, you need to do two things:

  1. Make g a number before giving it to math.sqrt. This can be done with either int or float.

  2. Convert the result back into a string to add it to the output string:

Below is a demonstration:

>>> import math
>>> g = int(input("Put your number here: "))
Put your number here: 7
>>> print ("The square root of you number is: " + str(int(math.sqrt(g))))
The square root of you number is: 2
>>>

Note however that the last line can be rewritten a little more cleanly like so:

print ("The square root of you number is: %d" % math.sqrt(g))

Upvotes: 1

Sergii Dymchenko
Sergii Dymchenko

Reputation: 7209

g = float(input("Put your number here: "))

With input() you get string, but float (or int) is needed.

Upvotes: 2

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