Reputation: 3
I'm generating dates using my code I want to exclude sunday and saturday please check my code here
for ($date = $start_date; $date <= $end_date; $date = date('Y-m-d', strtotime($date . ' + 1 day'))) {
$week = date('W', strtotime($date));
$year = date('Y', strtotime($date));
$from = date("Y-m-d", strtotime("$date"));
if ($from < $start_date)
$from = $start_date;
$to = date("Y-m-d", strtotime("$date-1day + 1 week"));
if ($to > $end_date) {
$to = $end_date;
}
if ($from <= $to) {
array_push($weekfrom, $from);
array_push($weekto, $to);
}
$n = count($weekfrom);
for ($i = 0; $i < $n; $i++) {
echo $weekfrom[$i];
}}
Upvotes: 1
Views: 2520
Reputation: 1
I used:
strtotime(sprintf('+%d weekday', 3));
if now is 15 sep(Wednesday), the example returns: 20 sep(exclude weekends)
Upvotes: 0
Reputation: 615
Just add this to beginning of your loop:
if(date("w", strtotime($date)) == 0 || date("w", strtotime($date)) == 6) continue;
Like this:
for ($date = $start_date; $date <= $end_date; $date = date('Y-m-d', strtotime($date . ' + 1 day'))) {
if(date("w", strtotime($date)) == 0 || date("w", strtotime($date)) == 6) continue;
$week = date('W', strtotime($date));
$year = date('Y', strtotime($date));
$from = date("Y-m-d", strtotime("$date")); //Returns the date of monday in week
if ($from < $start_date)
$from = $start_date;
$to = date("Y-m-d", strtotime("$date-1day + 1 week")); //Returns the date of sunday in week
if ($to > $end_date) {
$to = $end_date;
}
if ($from <= $to) {
array_push($weekfrom, $from);
array_push($weekto, $to);
}
$n = count($weekfrom);
for ($i = 0; $i < $n; $i++) {
echo $weekfrom[$i];
}}
Upvotes: 0
Reputation: 407
you can do like this.
$getDate = date('l', strtotime($date));
if ($getDate != 'Saturday' AND $getDate != 'Sunday') {
......
}
if that date not Saturday or Sunday, then process the thing.
Upvotes: 1