CODEWITHSUNDEEP
python
Eagle
Eagle

Reputation: 1197

Print frequency of words, in a sentence, in a single line

I have a sentence "The quick fox jumps over the lazy dog", and I have counted the number of times each word occurs in this sentence. The output should be like this:

brown:1,dog:1,fox:1,jumps:1,lazy:1,over:1,quick:1,the:2

There should be no spaces between the characters in this output, and there should be commas between the words/numbers. The output from my program looks like this: 

,brown:1,dog:1,fox:1,jumps:1,lazy:1,over:1,quick:1,the:2

I find that there is a comma place before 'brown'. Is there an easier way to print this? 

    filename = os.path.basename(path)


    with open(filename, 'r+') as f:
        fline = f.read()     
        fwords = fline.split()  

        allwords = [word.lower() for word in fwords]
        sortwords = list(set(allwords))


    r = sorted(sortwords, key=str.lower)

    finalwords = ','.join(r)

    sys.stdout.write(str(finalwords))
    print '\n'

    countlist = {}
    for word in allwords:
        try: countlist[word] += 1
        except KeyError: countlist[word] = 1       

    for c,num in sorted(countlist.items()):
        sys.stdout.write(",{:}:{:}".format(c, num))

Upvotes: 0

Views: 122

Answers (1)

mhlester
mhlester

Reputation: 23251

A couple alternate ways of making the word list. First, a one-liner:

countlist = {word:allwords.count(word) for word in allwords}

As pointed out by DSM, that method can be slow with long lists. An alternate would be to use defaultdict:

from itertools import defaultdict
countlist = defaultdict(int)
for word in allwords:
    countlist[word] += 1

For output, join individual word counts with a ,, which avoids having one at the beginning:

sys.stdout.write(",".join(["{:}:{:}".format(key, value) for key, value in countlist .items()]))

Upvotes: 1

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