CODEWITHSUNDEEP
phparrays
user2406735
user2406735

Reputation: 245

php check if all values from one two dimensional array are in another two dimensional array

I have a two, two dimensional arrayw like this. They are dynamicly created so they can have different numbers of arrays inside.

$userInput['shops'] = Array 
(
    [0] => Array 
    (
        [id] => 9
    )
)

and another that look like this:

$userShops = Array
(
    [0] => Array
    (
        [id] => 9
    )
    [1] => Array
    (
        [id] => 10
    )
)

First array is something that i receve from post, ids of selected shops. Second array shows all ids of shops that user have. How can i test if all values from userInput can be found in array userShops? I use this for validation so i need to see if all values from post matches the real values for user.

I have tried to do it like this but i receve oknot as result, so i think this should be constructed differently, maybe to somehow count matches...You should ignore my code because i think this is bad approach...In short i need to check if all values from first array can be found in second, if not than show an error.

if(isset($userInput['shops']) && is_array($userInput['shops'])){
    foreach($userInput['shops'] as $input){
        foreach($userShops as $userShop){
            if(in_array($input, $userShop)){
                print_r('ok');
            }
            else {
                print_r('not'); or show validation error
            }
        }
    }
    exit;
}

Upvotes: 1

Views: 50

Answers (1)

George Brighton
George Brighton

Reputation: 5151

How about something like this:

function flatten(array $data) {
    return array_map(function(array $element) {
        return $element['id'];
    }, $data);
}

$user = flatten($userInput['shops']);
$shops = flatten($userShops);

$isCovered = empty(array_diff($user, $shops));

Upvotes: 1

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