CODEWITHSUNDEEP
phparrays
Lee Price
Lee Price

Reputation: 5212

Determine whether Array 1 contains all values from Array 2

I have 2 arrays which might look something like this:

$a1 = array('c','b','a');
$a2 = array('a', 'b', 'c', 'd', 'e');

I need to somehow check whether every value in $a1 is present in $a2.

I've looked at array_diff and array_intersect but can't see how they can be used because the only return the values that are present and not present respectively.

Upvotes: 0

Views: 63

Answers (4)

Johannes Klauß
Johannes Klauß

Reputation: 11020

Look at this:

http://php.net/manual/de/function.in-array.php

Okay, I'll make it clearer:

The Function in_array() gives you a Boolean if the needle is in the haystack. So, a line like this will work for you:

$return = in_array($a1, $a2, true);

If $a1 is in $a2 the function returns true, otherwise false. The third Parameter activates strict search, so there won't be return even when a false would be right.

Upvotes: 1

Tobias
Tobias

Reputation: 883

function has_all_values($base, $comparing) {
    foreach($comparing as $value) {
        if(!in_array($base, $value))
            return false;
    }
    return true;
}

Upvotes: 0

aliz_bazar
aliz_bazar

Reputation: 292

You can use something like

sizeof(array_intersect($a1, $a2)) == sizeof($a1)

Upvotes: 0

Precastic
Precastic

Reputation: 4011

I am not sure what you mean by "present respectively" but array_diff is the function you are looking for. Just make sure you pass the arrays into the function in the correct order. Try:

// result = no
echo count( array_diff( $a1, $a2 ) ) ? 'yes' : 'no';
// result = yes
echo count( array_diff( $a2, $a1 ) ) ? 'yes' : 'no';

Upvotes: 2

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