CODEWITHSUNDEEP
phphtmlbuttonpostif-statement
Mrtata01
Mrtata01

Reputation: 23

how i can call the button inside the if statement PHP

I am a newbie I am having a little problem on how can i call the button inside my if statement. I am trying to work on a userlog where when you click a button it will output on the user log.

but how can i call the >> THE VIEW button inside my if statement so that it will fwrite inside the userlog.txt.

inside this if($_POST['submit'] = ") same goes in the search button and the add edit delete button. did u get my point?

<body background="images.jpg">
<?php
session_start();

if($_SESSION['username'])
{
echo "Welcome, ".$_SESSION['username']."!<br><a href='logout.php'>Logout</a><br>";
echo '<FORM METHOD="LINK" ACTION="mydata4.php">
<INPUT TYPE="submit" VALUE="Edit/Delete/add">
</FORM>';
echo '<FORM METHOD="LINK" ACTION="mydata2.php">
<INPUT TYPE="submit" VALUE="View" id="viewbutton">
</FORM>';
echo '<FORM METHOD="LINK" ACTION="display_data.php">
<INPUT TYPE="submit" VALUE="Search">
</FORM>';
}
else
{
die("You must be logged in!");
}


if($_POST['submit'] = ")
{   
$date=date("Y-m-d H:i:s");
$updatefile = "userlogs.txt";
$fh = fopen($updatefile, 'a') or die("can't open file");
$stringData = "User: $username click view button";
fwrite($fh, "$stringData".PHP_EOL);
fclose($fh);
}   
?>

Upvotes: 0

Views: 4638

Answers (3)

amit
amit

Reputation: 874

Use

if(isset($_POST))

instead of

if($_POST['submit'] = ")

Upvotes: 1

Tun Zarni Kyaw
Tun Zarni Kyaw

Reputation: 2119

you can set the same name to your submit buttons ...

<input type="submit" name="submit" value="View" />
<input type="submit" name="submit" value="Search" />

and in your PHP, you can simply use as you mentioned

if( $_POST["submit"] == "View" )
...
if( $_POST["submit"] == "Search" )
...

one more things is that, you have to use method="post" in your <form> tag if you want to use $_POST in php

<form method="post" action="....php">

Upvotes: 0

Zeeshan
Zeeshan

Reputation: 1675

try this... you are doing mistake in your if condition.

<body background="images.jpg">
<?php
session_start();

if($_SESSION['username'])
{
echo "Welcome, ".$_SESSION['username']."!<br><a href='logout.php'>Logout</a><br>";
echo '<FORM METHOD="LINK" ACTION="mydata4.php">
<INPUT TYPE="submit" VALUE="Edit/Delete/add">
</FORM>';
echo '<FORM METHOD="LINK" ACTION="mydata2.php">
<INPUT TYPE="submit" VALUE="View" id="viewbutton">
</FORM>';
echo '<FORM METHOD="LINK" ACTION="display_data.php">
<INPUT TYPE="submit" VALUE="Search" name="submit" id="submit">
</FORM>';
}
else
{
die("You must be logged in!");
}


if($_POST['submit'] == "submit")
{   
$date=date("Y-m-d H:i:s");
$updatefile = "userlogs.txt";
$fh = fopen($updatefile, 'a') or die("can't open file");
$stringData = "User: $username click view button";
fwrite($fh, "$stringData".PHP_EOL);
fclose($fh);
}   
?>

Upvotes: 0

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