CODEWITHSUNDEEP
pythonpython-3.xmatplotlib
user3301310
user3301310

Reputation: 1

Legend is outside the frame

import matplotlib.pyplot as plt

x, y = [1, 2, 3], [5, 7, 2]
fig = plt.figure()
ax  = fig.add_subplot(111)
ax.plot(x, y)
fig.tight_layout() #растягивает графики на всё окно
leg = ax.legend(['legend'], bbox_to_anchor = (1.0, 0.5), loc='upper left',)
plt.show()

Legend is outside the frame. I see part of the legend, but I want to see all. How to do it?

Upvotes: 0

Views: 327

Answers (1)

Lev Levitsky
Lev Levitsky

Reputation: 65791

This is what bbox_to_anchor does:

Users can specify any arbitrary location for the legend using the *bbox_to_anchor* keyword argument. bbox_to_anchor can be an instance of BboxBase(or its derivatives) or a tuple of 2 or 4 floats. For example:

loc = 'upper right', bbox_to_anchor = (0.5, 0.5)

will place the legend so that the upper right corner of the legend at the center of the axes.

So play around with that tuple, for example try bbox_to_anchor = (0.05, 0.95). Or just leave it out altogether, and the legend will be in the upper left corner.

Edit: If you want the legend to be out of the subplot, you can try the following:

import matplotlib.pyplot as plt

x, y = [1, 2, 3], [5, 7, 2]
fig = plt.figure()
ax = fig.add_axes((0.2, 0.05, 0.75, 0.9))
ax.plot(x, y)
leg = ax.legend(['legend'], bbox_to_anchor = (0, 0.9))
plt.show()

You can tweak the numbers to fine-tune the positions.

Upvotes: 3

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