CODEWITHSUNDEEP
php
Quinox
Quinox

Reputation: 97

PHP parse URL image directory

I have some script which output the images, with an interval of 5 seconds, on a screen. All images are in a directory called images/easter. The URL to display the webpage is http://'localhost'/index.php. In the index.php I have a variable: $directory = 'images/easter/.

We want users create a new image directory and upload pictures to it (eg images/holiday). The new images have to be displayed with a simple change in the url.

http://'localhost'/index.php?holiday

I think this can be done by URL parsing in PHP. But how to script this?

Thanks in advanced.

Upvotes: 0

Views: 236

Answers (4)

Alireza Amiri
Alireza Amiri

Reputation: 511

You can use $_GET parameters.

URL :

http://'localhost'/index.php?q=holiday

Code :

$directory = 'images/'((isset($_GET['q']))?$_GET['q']:'');

or 

if (isset($_GET['q']))
    $directory = 'images/'.$_GET['q'];
else
    $directory = 'images';

Upvotes: 0

Quinox
Quinox

Reputation: 97

Thanks so far for the answers.

We do not want to edit the files, so the change have to be in the URL from where the pictures are taken.

My knowledge of PHP is very limited.

Upvotes: 0

FlyingM
FlyingM

Reputation: 227

Use $_GET to retrieve the desired values from the URL. You'd have to adapt it slightly though. Maybe you want something like http://'localhost'/index.php?dir=holiday. That way, you can use $_GET on dir. PHP Form handling

Upvotes: 0

Tokk
Tokk

Reputation: 4502

just make your url something like

http://localhost/index.php?dir=holiday

or just

http://localhost/index.php

In your script do the following:

<?php
$directory = 'images/'.((isset($_GET['dir'])) ? $_GET['dir'] : 'easter');

But be sure to check weather the input is valid, so that it is not possible to output the content of a private folder.

If you want Urls like

http://localhost/holiday

you shold take a look at mod_rewrite

Upvotes: 1

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