CODEWITHSUNDEEP
pythonregexpattern-matchingdecimalmatch
jmoney
jmoney

Reputation: 23

Regex: match word and number with decimal

I would like to match words and numbers and drop all special characters unless it's a period between numbers.

Specifically, I want to have the effect of \W+ except instead of splitting 49.99 into 49 and 99, I want to keep it as 49.99

For example I want

"millie's math house 3-7 (win/mac) now 49.99 only."

to be split into

['millie', 'math', 'house', '3', '7', 'win', 'mac', 'now', '49.99', 'only']

But right now, using just \W+, I get

['millie', 'math', 'house', '3', '7', 'win', 'mac', 'now', '49', '99', 'only']

How can I keep words that have periods in the middle, but get rid of special characters otherwise?

Thanks!

Upvotes: 2

Views: 2763

Answers (3)

user590028
user590028

Reputation: 11730

You should try adding dot character, for example 

[\W.]+

Upvotes: 0

kabb
kabb

Reputation: 2502

Try the following

[^\w.]+

Instead of matching all non words characters, it matches everything that isn't a word character/period.

Upvotes: 2

Gi0rgi0s
Gi0rgi0s

Reputation: 1867

If you know for a fact there will be a decimal every time in the middle, then this is viable:

(\d+.\d+)

You can check the regular expression here:

regexpal.com

Upvotes: 1

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