Reputation: 1161
I have a list of tuples like:
a = [(1,2,3), (4,5)] // np.shape = (2,)
And i want to covert it into an array like structure, but of fixed shape, ie
a = [(1,2,3), (4,5,0)] // np.shape = (2,3)
Upvotes: 2
Views: 1867
Reputation: 239623
Functional way to do this would be
a = [(1,2,3), (4,5), (6, 7, 8, 9)]
from itertools import izip_longest
print zip(*izip_longest(*a, fillvalue = 0))
# [(1, 2, 3, 0), (4, 5, 0, 0), (6, 7, 8, 9)]
Upvotes: 3
Reputation: 34047
In [69]: maxlen=max(len(i) for i in a) #get the max length of all tuples
In [70]: [i+(0,)*(maxlen-len(i)) for i in a] #fill each tuple with extra zeros
Out[70]: [(1, 2, 3), (4, 5, 0)]
Upvotes: 3