CODEWITHSUNDEEP
htmlxmlxsltxslt-1.0
zeomega
zeomega

Reputation: 355

XSL get content by key from another xml child

Here is my example xml example :

<bloc id = "mybloc">
 <ref_ex ref = "data1"/>
 <ref_ex ref = "data2"/>
</bloc>

<ex id = "data1">
    <name>Hello</name>
    .. (something else)
</ex>
<ex id = "data2">
    <name>Hello Me !</name>
    .. (something else)
</ex>

I would like to get this html code like :

<a href="#data1">Hello</a>
<a href="#data2">Hello Me!</a>

I've tried with this xsl :

<xsl:stylesheet xmlns:xsl = "http://www.w3.org/1999/XSL/Transform" version = "1.0">
  <xsl:output method = "html"/>
    <xsl:template match = "ref_ex">
        <a href = "#{@ref}">
            <xsl:template match = "ex" use="@ref">
                <xsl:value-of select = "@name"/>
            </xsl:template>
        </a>
    </xsl:template>
</xsl:stylesheet>

but I get this error :

element template only allowed as child of stylesheet !

someone have any idea to do that ? by respecting my format.

Upvotes: 0

Views: 140

Answers (1)

Mathias M&#252;ller
Mathias M&#252;ller

Reputation: 22647

From the comments section: You simply cannot use xsl:template inside another xsl:template. Why? Because it makes awful little sense. I suggest you read about the basics of XSLT in order to understand the concept of tempate matches.

The stylesheet below transforms ex elements into a elements if their ID is referenced in a bloc element. Another viable solution, as suggested by @helderarocha, would be to use keys.

Assuming correct input (a root element to make it well-formed):

<root>
<bloc id = "mybloc">
 <ref_ex ref = "data1"/>
 <ref_ex ref = "data2"/>
</bloc>

<ex id = "data1">
    <name>Hello</name>
    <!--.. (something else)-->
</ex>
<ex id = "data2">
    <name>Hello Me !</name>
     <!--.. (something else)-->
</ex>
</root>

Stylesheet

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*"/>


<xsl:template match="/root">
    <xsl:copy>
        <xsl:apply-templates/>
    </xsl:copy>
</xsl:template>

<xsl:template match="bloc[@id='mybloc']">
    <xsl:apply-templates select="//ex[id = current()/ref_ex/@ref]"/>
</xsl:template>

<xsl:template match="ex">
    <a href="{@id}">
        <xsl:value-of select="."/>
    </a>
</xsl:template>

</xsl:stylesheet>

Output

<?xml version="1.0" encoding="UTF-8"?>
<root>
   <a href="data1">Hello</a>
   <a href="data2">Hello Me !</a>
</root>

Upvotes: 1

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