CODEWITHSUNDEEP
shellsh
Sohan
Sohan

Reputation: 6809

Shell script to accept special characters from input

I have script that accepts passwords from user. As we know passwords can have special characters. So there is case when user have some specific characters the script I wrote does not work.

Have a look

./passwrd.sh sohan$23
sohan3

Here is script snippet

#!/bin/sh
#=============================================================================
#
# DESCRIPTION
#
# Script for creating csbuser in weblogic
#
# USAGE ./create.sh <password>
# where password is OPTIONAL.

if [ $# -eq 1 ]; then
echo $1
#csb_password=`echo "$1" | sed -r 's/\$/\\\$/g'`
fi

Can anyone suggest me what can be done here.

Upvotes: 0

Views: 1563

Answers (1)

fedorqui
fedorqui

Reputation: 289505

When you call the script like ./passwrd.sh sohan$23, the $23 will be expanded.

To give it as a literal string, do use single quotes:

./passwrd.sh 'sohan$23'

EXample

$ cat a
#!/bin/bash

echo "the var is $1"

$ var=10
$ ./a a$var
the var is a10

$ ./a 'a$var'
the var is a$var

Upvotes: 1

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