CODEWITHSUNDEEP
c++listtypes
user3448085
user3448085

Reputation: 1

ERROR: list does not name a type (C++). I don't think so?

So I have been building on a small example of classes I found floating around to better prepare me for some C++ coding assignments in the future. Trying to compile this code gives me an error: "classExample.cpp:12:2: error: 'list' does not name a type".

The only problem is, I most definitely assigned it's type to be of Rectangle* as you can see in the code below. What am I doing wrong?

// classes example
#include <iostream>
#include <stdlib.h>
#include <string>
#include <sstream>

using namespace std;

class setOfRectangles {
    list<Rectangle*> rectangles;
};

class Rectangle {
    int width, height; //class variables

  public:   //method constructors
    Rectangle(){width = 0;  //constructor for rectangle
        height = 0;}
    Rectangle(int i, int j){width = i; height=j;}
    void set_values (int,int);
    string toString();
    int area() {return width*height;}
    int perimeter(){return (2*width)+(2*height);}
};

void Rectangle::set_values (int x, int y) { //fleshing out class method
  width = x;
  height = y;
}

string Rectangle::toString()
{
    /*
        Prints information of Rectangle
        Demonstrates int to string conversion (it's a bitch)
    */

    std::stringstream sstm; //declare a new string stream

    sstm << "Width = ";
    sstm << width;

    sstm << "\n";

    sstm << "Height = ";
    sstm << height;

        sstm << "\n";

    sstm << "Perimeter = ";
    sstm << perimeter();

    sstm << "\n";

    return sstm.str(); //return the stream's string instance
}

int main (int argc, char* argv[]) {
    if(argc != 3)
    {
        cout << "Program usage: rectangle <width> <height> \n";
        return 1;
    }   
    else
    {
        Rectangle rect = Rectangle(2,3); //new instance, rectangle is 0x0
        cout << "area: " << rect.area() << "\n";
        cout << rect.toString() << endl;

        //call this method
        rect.set_values (atoi(argv[1]),atoi(argv[2]));

        cout << "area: " << rect.area() << "\n";
        cout << rect.toString() << endl;
        return 0;
    }
}

Upvotes: 0

Views: 1409

Answers (1)

jpw
jpw

Reputation: 44931

You need to include the proper header for list: #include <list>

Also, why are you including the C header <stdlib.h> in a C++ application? Is it for atoi? If so, you should look into how to do casts in C++ in the proper way. Or include <cstdlib> instead (which is the C++ version of the same header).

Also, you need to move this:

class setOfRectangles {
    list<Rectangle*> rectangles;
};

to after the declaration of class Rectangle, or the compiler won't know what a Rectangle is.

Upvotes: 2

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