CODEWITHSUNDEEP
phpregex
user3462177
user3462177

Reputation: 1

Insert string after images on content

i have a string as

<p>content</p>
<p><img src="1.jpg" alt="alt image 1"></p>
<p>other content</p>
<p><img src="2.jpg" alt="alt image 2"></p>

i want to get alt images and insert after image, like

<p>content</p>
<p><img src="1.jpg" alt="alt image 1"></p><p>alt image 1</p>
<p>other content</p>
<p><img src="2.jpg" alt="alt image 2"></p><p>alt image 2</p>

i know get alt by 

preg_match_all("/< *img[^>]*alt *= *[\"\']?([^\"\']*)/i",$str,$alt);
foreach ($alt[1] as $alti) {
$altimg[]=$alti;
}

and i was try this code

for($i=0;$i < count($alt[1] );$i++){
    $regex = '#<img.+?src="([^"]*)".*?/?>#i';
    $replace = '$0<div>'.$altimg[$i].'</div>';
}
$str = preg_replace($regex, $replace, $str);

but the result show 

<p>content</p>
<p><img src="1.jpg" alt="alt image 1"></p><p>alt image 2</p>
<p>other content</p>
<p><img src="2.jpg" alt="alt image 2"></p><p>alt image 2</p>

please tell me how to fix this, thank for your help and Sorry for my bad english.

Upvotes: 0

Views: 129

Answers (3)

gabrieloliveira
gabrieloliveira

Reputation: 570

This can solves problem:

$regex = '#<img.+?src="([^"]*)".*?alt *= *[\"\']?([^\"\']*)[\"\']?.*?/?>#i';
$replace = '$0<p>$2</p>';
$str = preg_replace($regex, $replace, $str);

Upvotes: 1

flauntster
flauntster

Reputation: 2016

Your line

$str = preg_replace($regex, $replace, $str);

is outside of the loop and will be running with the last value of $regex & $replace after exiting the for loop, hence it's inserting the last found alt.

Upvotes: 0

Praveen Kumar Purushothaman
Praveen Kumar Purushothaman

Reputation: 167182

You can do in two ways:

  1. Easy client-side way:

    $("img").closest("p").after("<p>Content</p>");

  2. Tough PHP Way using Simple HTML DOM Parser:

    $html = '';
foreach($html->find('img') as $element) 
   echo $element->src . '<br>';

Upvotes: 0

Related Questions