Reputation: 57
I've got an array which contains an entire column from my csv file which has a lot of duplicates since the csv consist of users their contact info and their current group.
So the users in the CSV are in a group but sometime multiple users are in the same group now the point of this python script is to sort all the users that are in the same group in a row like. I'll update the main thread so it wont confuse more people sorry.
The end goal is of this script will be to put the group in a row together with the phone numbers of the users that are in that group like this.
GroupName, PhoneNumber1, PhoneNumber2, PhoneNumber3, PhoneNumber4, etc
Example:
Name, email, phonenumber, **group**
name1, name2, number1, ExampleGroup
So I've tried sorting it by using this: https://wiki.python.org/moin/HowTo/Sorting
And it returns:
['a', ' ', 'E', 'g', 'i', 's', 'm', 'M', 'L', 'o', 'l', 'p', 'S', 'R', 't', 'h', 'e', 'n']
The code I'm using at the moment:
import csv
with open('Configtool.csv', 'rb') as f:
reader = csv.reader(f, delimiter=';', quoting=csv.QUOTE_NONE)
for row in reader:
groupname = row[5]
#print groupname
sortedgroup = list(set(groupname))
print sortedgroup
Your help is much appreciated,
Upvotes: 1
Views: 57
Reputation: 1087
You are converting to set first. So set method sees a string and it extracts its characters and creates a set out of them.
Try list first and set next - set(list(groupname)). This is if you want to extract the unique items from the list
However sorting might still need applying sorted method.
*I answered but now I am not sure what you need. Please ignore if this does not help.
Upvotes: 1