CODEWITHSUNDEEP
batch-file
FrinkTheBrave
FrinkTheBrave

Reputation: 3958

Get value of nested variable name in batch script

I have a subroutine which uses parameter to return a string. As part of my logging I want to display the returned parameter value before I exit the routine.

Easier to explain in code!

@ECHO OFF
SET MYVAL=1
ECHO Before MYVAL=%MYVAL%
CALL :SETMYVAL MYVAL
ECHO After  MYVAL=%MYVAL%
PAUSE
EXIT /b 0

:SETMYVAL
SET "%~1=2"
ECHO SETMYVAL called, returning %~1=%~1
GOTO :EOF

The above code produces:

Before MYVAL=1
SETMYVAL called, returning MYVAL=MYVAL
MYVAL=2
Press any key to continue . . .

But I want the last line ofthe subroutine to output

SETMYVAL called, returning MYVAL=2

Any ideas (without moving the line, or using extensions or delayed expansion)

Upvotes: 2

Views: 104

Answers (3)

FrinkTheBrave
FrinkTheBrave

Reputation: 3958

Thanks foxidrive, the best I could come up with is:

:SETMYVAL
SET "%~1=2"
ECHO ECHO %%%~1%%>"%TEMP%\SETMYVAL.bat"
FOR /F "tokens=*" %%A IN ('CALL "%TEMP%\SETMYVAL.bat"') DO (CALL :SETMYVALFROMFILE %%A)
ECHO SETMYVAL called, returning %~1=%MYTEMP%
GOTO :EOF
:SETMYVALFROMFILE
SET MYTEMP=%~1
GOTO :EOF

Nasty eh?

Upvotes: 0

foxidrive
foxidrive

Reputation: 41234

Your case is artificial, so you may not get a real life solution.

@ECHO OFF
SET MYVAL=1
ECHO Before MYVAL=%MYVAL%
CALL :SETMYVAL MYVAL
ECHO After  MYVAL=%MYVAL%
PAUSE
EXIT /b 0

:SETMYVAL
SET "val=2" & call SET "%~1=%%val%%"
ECHO SETMYVAL called, returning %~1=%val%
GOTO :EOF

Upvotes: 1

npocmaka
npocmaka

Reputation: 57252

ECHO SETMYVAL called, returning %~1=2

This should do it....

Or

ECHO SETMYVAL called, returning %~1=%MYVAL%

or 

call ECHO SETMYVAL called, returning %~1=%%%~1%%

Upvotes: 1

Related Questions