CODEWITHSUNDEEP
parsingerlang
Ashley
Ashley

Reputation: 21

Parse error using yecc in Erlang: "syntax error before"

I am currently writing a parser with yecc in Erlang. 

Nonterminals expression.

Terminals '{' '}'  '+' '*' 'atom' 'app' 'integer' 'if0' 'fun' 'rec'.

Rootsymbol expression.

expression -> '{' '+' expression  expression '}' : {'AddExpression', '$3','$4'}.
expression -> '{' 'if0' expression expression expression '}' : {'if0', '$3', '$4', '$5'}.
expression -> '{' '*' expression expression '}' : {'MultExpression', '$3','$4'}.
expression -> '{' 'app' expression expression '}' : {'AppExpression', '$3','$4'}.
expression -> '{' 'fun' '{' expression '}' expression '}': {'FunExpression', '$4', '$6'}.
expression -> '{' 'rec' '{' expression expression '}' expression '}' : {'RecExpression', '$4', '$5', '$7'}.
expression -> atom : '$1'.
expression -> integer : '$1'.

I also have an erlang project that tokenizes the the input before parsing:

tok(X) ->
element(2, erl_scan:string(X)).

get_Value(X)->
 element(2, parse(tok(X))).

These cases are accepted: 

interp:get_Value("{+ {+ 4 6} 6}").
interp:get_Value("{+ 4 2}").

These return: {'AddExpression' {'AddExpression' {integer, 1,6} {integer,1,6}}{integer,1,6}} and {'AddExpression' {integer,1,4} {integer,1,2}}

But this test case:

interp:get_Value("{if0 3 4 5}").

Returns:

{1,string_parser,["syntax error before: ","if0"]}

Upvotes: 2

Views: 348

Answers (1)

rvirding
rvirding

Reputation: 20926

In the grammar rules what you are showing are the category of the terminal tokens and not their values. So you can match against an atom but not against a specific atom. If you are using the Erlang tokenizer then the token generated for "if0" will be {atom,Line,if0} while in you grammar you want a {if0,Line} token. This is what the "Pre-processing" section of the yecc documentation is trying to explain.

You will need a special tokenizer for this. A simple way of handling this if you want to use the Erlang tokenizer is have a pre-processing pass which scans the token list and converts {atom,Line,if0} tokens to {if0,Line} tokens.

Upvotes: 1

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