CODEWITHSUNDEEP
datexslt
ramu246
ramu246

Reputation: 51

automatic date generating in xsl

In my style sheet, in header position I have a date column in which the date should be the current date.

How can I do that?

My xsl file

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:fo="http://www.w3.org/1999/XSL/Format"

<fo:table-row>
    <fo:table-cell border="solid" border-width="1pt" padding-left="-7mm">
        <fo:block>
            DATE
        </fo:block>
    </fo:table-cell>
    <fo:table-cell border="solid" border-width="1pt" padding-left="-9mm">
        <fo:block>

            current date should come here

        </fo:block>
    </fo:table-cell>
</fo:table-row>

Upvotes: 1

Views: 1134

Answers (3)

user2532030
user2532030

Reputation: 655

For XSLT 1 you can use this:

<xsl:value-of select="document(&apos;http://xobjex.com/service/date.xsl&apos;)/date/utc/@rfc-822"/>

You can then use substrings or an xsl:choose to format the date to your needs

Upvotes: 2

michael.hor257k
michael.hor257k

Reputation: 117073

If you are using XSLT 1.0, you need to either:

(1) Pass the current date to the stylesheet as a parameter during runtime;

or

(2) Use the EXSLT date:date-time() extension function, which most (but not all) XSLT 1.0 processors support.

Upvotes: 1

vels4j
vels4j

Reputation: 11298

XSL Version 2.0 :

    <fo:block>
        <xsl:value-of  select="current-dateTime()"/>
    </fo:block>

Format DateTime :

  <xsl:value-of select="format-dateTime(current-dateTime(),'[D]-[MN]-[Y] [FN] at [H]:[m01]:[s01]')"/>

Upvotes: 1

Related Questions