CODEWITHSUNDEEP
python
DeadEli
DeadEli

Reputation: 1053

How to check if len is valid

I have a function

def foo(bar):
    #do some things
    len(bar)

If I call

foo(42)

it throws an exception of

TypeError: object of type 'int' has no len()

How do I check if the entered value can be used with len()?

Upvotes: 40

Views: 22445

Answers (4)

Martijn Pieters
Martijn Pieters

Reputation: 1121744

You can test if the object is Sized:

import collections.abc

if isinstance(bar, collections.abc.Sized):

The isinstance() test is true if all abstract methods of Sized are implemented; in this case that's just __len__.

Personally, I'd just catch the exception instead:

try:
    foo(42)
except TypeError:
    pass  # oops, no length

Upvotes: 29

Nathaniel Flath
Nathaniel Flath

Reputation: 16015

You can do:

if hasattr(bar, '__len__'):
    pass

Alternatively, you can catch the TypeError.

Upvotes: 53

alecxe
alecxe

Reputation: 473853

Since len() calls __len__() magic method under the hood, you can check if an object has __len__ method defined with the help of hasattr():

>>> def has_len(obj):
...     return hasattr(obj, '__len__')
... 
>>> has_len([1,2,3])
True
>>> has_len('test')
True
>>> has_len(1)
False

Upvotes: 8

sshashank124
sshashank124

Reputation: 32189

You can do it using try and except for best results:

def foo(bar):
    #do some things
    try:
        print(len(bar))
    except TypeError:
        print('Input not compatible with len()')

Upvotes: 5

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