CODEWITHSUNDEEP
maxima
mr_nobody
mr_nobody

Reputation: 194

Function with other function as argument

Please, tell me how use functions in Maxima? I tried this

function(g, u):= (print(g(0)), print(u));
function(x^2, 10);

but it doesn't work

Upvotes: 1

Views: 563

Answers (2)

Dr Potato
Dr Potato

Reputation: 178

When defining a function F(Y) you want Y to be a x-dependent input variable for the former, right?

You can directly define the a function F of unknown variable Y and then input some function as argument.

(%i_)   F(Y) := diff(Y(t),t) + Y(t^2);
        F(sin);

(%o_)   F(Y):='diff(Y(t),t,1)+Y(t^2)
(%o_)   sin(t^2)+cos(t)

and you are done!

If you try to parse F(foo(x)):=something + foo(x) you get

define: in definition of F, found bad argument foo(x)

There is a more specific way I took from maxima: use function as function argument: Before defining F(foo), you can tell maxima "by foo I mean foo(x)": depends(foo,x).

Then you can define a function with variable foo, for example

depends(foo,x);
F(foo) := foo(x^2) + foo(x) + diff(foo(x),x) ;
F(sin);

Upvotes: 0

Robert Dodier
Robert Dodier

Reputation: 17595

I guess you want to evaluate the first argument with a specific value of the second argument. So maybe you want ev(g, x=0) instead of g(0).

(g(0) works only if g is the name of a function or a lambda expression, i.e., an unnamed function.)

Maybe you can explain in more detail what you want to accomplish.

Upvotes: 3

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