CODEWITHSUNDEEP
maxima
booNlatoT
booNlatoT

Reputation: 611

Altering function argument on return

Suppose the following example

g(x):=block([],
  x:x+1
);

xx:1$;
g(xx)$;
xx;

This outputs 1. How can I have it output 2?

Edit: I searched for "maxima" combined with "pass by reference" and the results don't seem to suggest that "pass by reference" is really a thing defined in Maxima but if you know what I mean, that's what I want.

Upvotes: 2

Views: 47

Answers (2)

ejbarth
ejbarth

Reputation: 11

I think your trouble is simply that you have both % and ; in the xx assignment line.

Here's what works for me:

g(x):=block([],
  x:x+1
);

xx:1;

g(xx);

Upvotes: 1

slitvinov
slitvinov

Reputation: 5768

You can use a macro (an utility that generates maxima code).

(%i1) g(x)::=buildq([x], x : x + 1) $
(%i2) a: 1 $
(%i3) g(a) $
(%i4) a ;
(%o4)                                  2

Upvotes: 1

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