CODEWITHSUNDEEP
julia
Mageek
Mageek

Reputation: 4901

Julia: calling Array() with an array of dimensions

Suppose I want to create a multidimensional array whose dimensions / size per dimension are specified in an array. I want to do something like this:

dims = [2,5,6] # random example, the idea is I don't know dims ahead of time
arr = Array(Float64, dims)

That is not allowed. In the above case one should use:

arr = Array(Float64, dims[1], dims[2], dims[3] )

I don't know the length of dims ahead of time, so the above solution doesn't work for me. Is there a clean workaround outside of using some nasty sprintfs and eval?

Thanks!

Upvotes: 6

Views: 206

Answers (1)

one-more-minute
one-more-minute

Reputation: 1406

A really useful operator to remember in Julia is the “splat”, .... In this case you simply want:

arr = Array(Float64, dims...)

Upvotes: 10

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