Reputation: 5255
I consider that Phoenix lambda functions is somehow C++11 lambda. So I try the following:
http://coliru.stacked-crooked.com/a/38f1a2b655ea70fc
#include <boost/phoenix.hpp>
#include <iostream>
#include <ostream>
using namespace std;
using namespace boost;
using namespace phoenix;
using namespace arg_names;
using namespace local_names;
struct FakeOne{
int field;
};
int main()
{
auto k = FakeOne();
auto fn = (lambda(_a=k)[_a.field ]);
cout <<
fn()
<< endl;
}
Which throws:
main.cpp:20:32: error: 'const _a_type' has no member named 'field'
auto fn = (lambda(_a=k)[_a.field ]);
Upvotes: 1
Views: 160
Reputation: 393114
You can't just invoke members on placeholders (like _a) since they don't declare the members (like field
). Instead, bind them:
auto fn = phx::bind(&FakeOne::field, k);
Update To the comment:
#include <boost/phoenix.hpp>
namespace phx = boost::phoenix;
using namespace phx::local_names;
struct FakeOne{
int field;
};
auto k = FakeOne { 3 };
int main()
{
auto fn = phx::bind(&FakeOne::field, k);
k.field = 99;
return fn();
}
Compiles down to
main: ; test.cpp:13
movl k(%rip), %eax ; boost/boost/proto/expr.hpp:65
movl $99, k(%rip) ; test.cpp:16
ret
on GCC -O3
Upvotes: 1