CODEWITHSUNDEEP
scala
Themerius
Themerius

Reputation: 1911

Replace all invalid escape characters

The scala StringContext has problems with invlaid escape characters. Example:

s"""v \C/R\ni"""

Raises "scala.StringContext$InvalidEscapeException: invalid escape character at index 2". http://www.scala-lang.org/api/current/index.html#scala.StringContext$$InvalidEscapeException

Is there an elegant and universal way to avoid this problem? Especially the valid escape characters should be preserved. Possible would be:

s"""v \\C/R\ni"""

Just for info: I'll pipe such strings into a scala interpreter, so it is possible to prepare the string.

At a pinch replace * with \* but not the ones from chapter 1.3.6 will do. Any clever ideas?

(I'm using scala 2.11.x)

Upvotes: 2

Views: 7898

Answers (1)

Themerius
Themerius

Reputation: 1911

My solution at the moment:

val regex = "\\\\[^btnfr\"]".r
var str = """hi \C ho \t jo \n \" mu \M"""
val matches = regex.findAllIn(str).toList
val chars = matches.map(_(1))
for ( (x,y) <- matches zip chars) str = str.replace(x, "\\\\" + y)

The output is """hi \C ho \t jo \n \" mu \M""". Not very elegant, but it works. Maybe someone has an better, more "functional" solution?

Upvotes: 1

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