Reputation: 1326
My script:
#!/usr/bin/env bash
PATH=/home/user/example/foo/bar
mkdir -p /tmp/backup$PATH
And now I want to get first folder of "$PATH": /home/
cd /tmp/backup
rm -rf ./home/
cd - > /dev/null
How can I always detect the first folder like the example above? "dirname $PATH" just returns "/home/user/example/foo/".
Thanks in advance! :)
Upvotes: 24
Views: 84124
Reputation: 1582
To get the first directory component of VAR:
echo ${VAR%${VAR#/*/}}
So, if VAR="/path/to/foo"
, this returns /path/
.
Explanation:
${VAR#X}
strips off the prefix X
and returns the remainder. So if VAR=/path/to/foo
, then /*/
matches the prefix /path/
and the expression returns the suffix to/foo
.
${VAR%X}
strips off the suffix X
. By inserting the output of ${VAR#X}
, it strips off the suffix and returns the prefix.
If you can guarantee that your paths are well formed this is a convenient method. It won't work well for some paths, such as //path/to/foo
or path/to/foo
, but you can handle such cases by breaking down the strings further.
Upvotes: 4
Reputation: 2206
You can use dirname
...
#/usr/bin/env bash
DIRECTORY="/home/user/example/foo/bar"
BASE_DIRECTORY=$(dirname "${DIRECTORY}")
echo "#$BASE_DIRECTORY#";
Outputs the following...
/home/user/example/foo
Upvotes: -1
Reputation: 551
Pure bash:
DIR="/home/user/example/foo/bar"
[[ "$DIR" =~ ^[/][^/]+ ]] && printf "$BASH_REMATCH"
Easy to tweak the regex.
Upvotes: 0
Reputation: 626
You can try this awk command:
basedirectory=$(echo "$PATH" | awk -F "/" '{print $2}')
At this point basedirectory
will be the string home
Then you write:
rm -rf ./"$basedirectory"/
Upvotes: 8
Reputation: 1326
I've found a solution:
#/usr/bin/env bash
DIRECTORY="/home/user/example/foo/bar"
BASE_DIRECTORY=$(echo "$DIRECTORY" | cut -d "/" -f2)
echo "#$BASE_DIRECTORY#";
This returns always the first directory. In this example it would return following:
#home#
Thanks to @condorwasabi for his idea with awk! :)
Upvotes: 45
Reputation: 786329
To get the first firectory:
path=/home/user/example/foo/bar
mkdir -p "/tmp/backup$path"
cd /tmp/backup
arr=( */ )
echo "${arr[0]}"
PS: Never use PATH variable in your script as it will overrider default PATH and you script won't be able to execute many system utilities
EDIT: Probably this should work for you:
IFS=/ && set -- $path; echo "$2"
home
Upvotes: 1
Reputation: 75618
If PATH
always has an absolute form you can do tricks like
ROOT=${PATH#/} ROOT=/${ROOT%%/*}
Or
IFS=/ read -ra T <<< "$PATH"
ROOT=/${T[1]}
However I should also add to that that it's better to use other variables and not to use PATH
as it would alter your search directories for binary files, unless you really intend to.
Also you can opt to convert your path to absolute form through readlink -f
or readlink -m
:
ABS=$(readlink -m "$PATH")
You can also refer to my function getabspath.
Upvotes: 7