Pawan
Pawan

Reputation: 32321

How to remove the last bracket in this case

This is my program

package com.util;

public class SplitBy {

    public static void main(String args[]) {

        String name = "Masala Roasted with peanuts(49)";
        String category_id = "";

        if (!name.contains(",")) {
            if (name.contains("(")) {
                String[] parts = name.split("\\(");
                category_id = parts[1];

                System.out.println(category_id);
            }
        }

    }

}

With this the current output is

49)

Please let me know how to get rmove the closing bracket and produce only

49

Upvotes: 1

Views: 188

Answers (4)

robenrajan
robenrajan

Reputation: 355

Check this out

package com.util;

public class SplitBy {

    public static void main(String args[]) {

        String s = "";
        Pattern pattern = Pattern.compile("(?<=)(\\d+)");
        String EXAMPLE_TEST = "Masala Roasted with peanuts(49)";
        Matcher matcher = pattern.matcher(EXAMPLE_TEST);

        while (matcher.find()) {
            s = matcher.group(1);
        }
        System.out.println(s);
    }

}

Upvotes: 0

Florent Bayle
Florent Bayle

Reputation: 11890

You can split the String on both brackets:

String[] parts = name.split("[()]");

[()] is a regular expression matching both the openning and closing brackets. As split() is splitting the String around matches, the closing bracket will not be included in the resulting value.

According to the split() javadoc,

Trailing empty strings are therefore not included in the resulting array.

which means that it won't add an empty element at the end of your array.

Upvotes: 3

gpu3d
gpu3d

Reputation: 1184

You can look for both parentheses and only print the content in between:

category_id = name.substring(name.indexOf("(")+1, name.indexOf(")"));

Upvotes: 0

Deutro
Deutro

Reputation: 3313

You can do something like this:

category_id = category_id.substring(0, category_id.length() - 1);

Which will remove the last character from your String.

Upvotes: 2

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