Reputation: 131
I'm trying to find the trajectory an object would take (assuming air drag is negligible and trajectory angle is always between 0 and 90), including peak height. Here's what I know:
For me the problem could be reduced to 2d space, so if an object travels a horizontal distance of 8 meters starting at an elevation of 0 and ending at a relative elevation of -5 meters, and travels for 2 seconds. What was the peak height, and at what point in time did it reach that peak hight.
Also, trying to write this equation in to php, C, or objective C. Thanks
Upvotes: 1
Views: 1508
Reputation: 51933
I assume cannon ball like trajectory
So
solve the equations to find missing data
g=9.81; // [m/s^2]
t=!; // [s] time in air
p0(x0,y0)=!; // [m] start point
p1(x1,y1)=!; // [m] end point
v0(vx0,vy0)=?; // [m/s] start velocity vector
// Y axis free fall with initial velocity
y1=y0+vy0*t-0.5*g*t*t
vy0=(y1-y0+0.5*g*t*t)/t
vy0=(y1-y0)/t+0.5*g*t
// X axis constant speed
vx0=(x1-x0)/t
trajectory path point
x=x0+vx0*t;
y=y0+vy0*t-0.5*g*t*t;
where t = <0.0,time_in_air>
so for plotting do some for
loop through t
peak point:
vy(t)=vy0-g*t;
// for peak the y velocity is zero so
0.0=vy0-g*t;
t=vy0/g;
where t
is the time when object reach peak point. If you need coordinates then compute them like in bullet #2
Upvotes: 1