CODEWITHSUNDEEP
bash
Zack
Zack

Reputation: 1245

Bash script call a function in a different file

I am using bash script to call a function in a different file. But, the function didn't seem to run. I couldn't figure out what's the issue here. The following is part of the script: 

#!/bin/bash
source utility
res=$(InterCombinations)

File: utility

InterCombinations()
{
   ...
   echo "InterCombinations is called"
}

Please let me know if you need more info.

Thanks.

Upvotes: 2

Views: 229

Answers (1)

Satyajit R
Satyajit R

Reputation: 72

The scripts will work provided the utility file is in the current working directory. You could put or echo the variable:

set -x

in your main script to watch the steps in execution:

#!/bin/bash -ex
set -x
source utility
res=$(InterCombinations)

You are saving the output of your called function on to a variable and not echoing/printing it on to the "stdout".

Upvotes: 2

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