Reputation: 669
Say that you define a callback function as such:
typedef std::function<void(float)> Callback;
And you have a function as such:
void ImAFunction(float a)
{
//Do something with a
}
Is there a way to be able to store a function without an argument then pass one to it at a later time?
Such as this:
//Define the Callback storage
Callback storage;
storage = std::bind(ImAFunction, this);
//Do some things
storage(5);
This wont work which I explain with some of my real code below.
I can get close to what I wan't if I bind the value in with the std::bind function. Such as:
//Change
//storage = std::bind(ImAFunction, this);
storage = std::bind(ImAFunction, this, 5.0); //5.0 is a float passed
This works but when I go to pass a value through the function the outcome is whatever I set it to before:
storage(100); //Output is still 5
I am basing the fact that I think this is possible on this article.
http://www.cprogramming.com/tutorial/function-pointers.html
It doesn't use the function or bind functions but it does pass pointer arguments and performs exactly what I need. The reason I don't just skip the bind function is because I am trying to store the function in a class (private) and I can't store it if it's a template because it's created with the class.
The error produced above comes from this code:
struct BindInfo {
Callback keyCallback;
int bindType;
bool isDown;
bool held;
std::string name;
};
template <class T1>
void bindEvent(int bindType, T1* keydownObj, void(T1::*keydownF)(float), std::string name)
{
BindInfo newKeyInfo = { std::bind(keydownF, keydownObj), bindType, false, false, name };
inputBindings.insert(std::pair<int, BindInfo>(BIND_NULL, newKeyInfo));
};
The error is:
No viable conversion from '__bind<void(Main::*&)(float), Main *&>' to 'Callback' (aka 'function<void (float)>'
Is this possible? Thanks in advance.
Upvotes: 1
Views: 1352
Reputation: 64
It sounds like what you're looking for is a function pointer. While I don't have a lot of experience using them in C++ I have used them in C so: Yes, it is possible. Perhaps something like this:
void (*IAmAFunctionPointer)(float) = &IAmAFunction;
The best way to think about that line is, that IAmAFunctionPointer is a pointer (hence the *), it returns a void, and takes a float. Then later:
float a = 5;
IAmAFunctionPointer(a);
You could even design it so that the callback function is passed into the method (I assume this is what you're looking for).
void DoStuffThenCallback(float a, void (*callback)(float))
{
//DoStuff
callback(a);
}
further reading: http://www.cprogramming.com/tutorial/function-pointers.html
Upvotes: 0
Reputation: 254471
You can include a placeholder for an unbound argument:
std::bind(&Main::ImAFunction, this, std::placeholders::_1);
If you find that a bit of a mouthful, a lambda might be more readable:
[this](float a){ImAFunction(a);}
Upvotes: 2