CODEWITHSUNDEEP
javamathdoubleexponentsquare-root
Sam Mitchell
Sam Mitchell

Reputation: 194

Java root and power of

I'm having trouble figuring this out:

Write a fragment that uses a for statement to set the double variable sum to the value of: enter image description here

Here's what I tried:

class thing 
{
  public static void main (String [] args)
  {
    double sum = 1;
    for (int i = 1; i<=25; i++)
    {
      sum += Math.pow(i,1.0/i) ;
      System.out.println(sum);
    }
  }
}

I know this is wrong because it does not end with the proper calculation of 1.137411462. Any help is appreciated! :)

Upvotes: 2

Views: 1732

Answers (2)

RizJa
RizJa

Reputation: 2031

To add to the other replies above, that sum must start with 0, the calculation as you described isn't accurate.

The value of 25√25 is 1.137411462, not the sum from 1 to 25, in which case if you start with

int sum = 0;

You end up with the total: 30.85410561309813 which is the correct total that you want.

Upvotes: 2

Madhawa Priyashantha
Madhawa Priyashantha

Reputation: 9862

change sum to zero at start .you are adding additiona 1 to sum.

double sum = 0;

for (int i = 1; i<=25; i++)
{
  sum += Math.pow(i,1.0/i) ;

}

  System.out.println(sum);

Upvotes: 2

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