Reputation: 821

Making Bash modular

I have a bunch of Bash scripts and they each make use of the following:

BIN_CHATTR="/usr/bin/chattr"
BIN_CHKCONFIG="/sbin/chkconfig";
BIN_WGET="/usr/bin/wget";
BIN_TOUCH="/bin/touch";
BIN_TAR="/bin/tar";
BIN_CHMOD="/bin/chmod";
BIN_CHOWN="/bin/chown";
BIN_ECHO="/bin/echo";
BIN_GUNZIP="/usr/bin/gunzip";
BIN_PATCH="/usr/bin/patch";
BIN_FIND="/usr/bin/find";
BIN_RM="/bin/rm";
BIN_USERDEL="/usr/sbin/userdel";
BIN_GROUPDEL="/usr/sbin/groupdel";
BIN_MOUNT="/bin/mount";

Is there a way I could just wget a Bash script with global settings like that and then include them in the script I want to run?

Upvotes: 3

Answers (4)

linuxfan

Reputation: 1160

Yes you can. Just add your variables and functions to a file, make it executable and "execute" it at the top of any script that needs to access them. Here's an example:

$ pwd
/Users/joe/shell

$ cat lib.sh 
#!/bin/bash
BIN_WGET="/usr/bin/wget"
BIN_MOUNT="/bin/mount"

function test() {
    echo "This is a test"
}

$ cat script.sh 
#!/bin/bash

. /Users/joe/shell/lib.sh

echo "wget=$BIN_WGET"

test


$ ./script.sh 
wget=/usr/bin/wget
This is a test

Upvotes: 2

Michael D.

Reputation: 1837

are you looking for the source command?

mylib.sh:

#!/bin/bash
JAIL_ROOT=/www/httpd
is_root(){
   [ $(id -u) -eq 0 ] && return $TRUE || return $FALSE
}

test.sh

#!/bin/bash
# Load the  mylib.sh using source comamnd
source mylib.sh

echo "JAIL_ROOT is set to $JAIL_ROOT"

# Invoke the is_root() and show message to user
is_root && echo "You are logged in as root." || echo "You are not logged in as root."

btw - use rsync -a to mirror scripts with +x flag.

Upvotes: 2