CODEWITHSUNDEEP
pythonlist
user2983594
user2983594

Reputation: 101

How do I print separate items from list in Python?

for example I have a list

data=[[1, 2, 3, 4, 5, 6, 7], [2, 4, 3, 6, 5]]

I want to print numbers 1, 3, 4 from the first array of data I can't find how can i print it My code so far

print(data[0][0:4])

how can I make it not to print 2 (I'm using python 3.2)??

Upvotes: 0

Views: 232

Answers (5)

chfw
chfw

Reputation: 4592

Here's my take on it:

>>> import pyexcel as pe
>>> data=[[1,2,3,4,5,6,7],[2,4,3,6,5]]
>>> m=pe.sheets.MultipleFilterableSheet(data)
>>> # get rid of other columns
>>> m.filter(pe.filters.ColumnFilter([1,4,5,6]))
>>> print(pe.utils.to_array(m))
[[1, 3, 4], [2, 3, 6]]
>>> print m.row[0]
[1, 3, 4]
>>> print m.row[0][0:3]
[1, 3, 4]

Upvotes: 0

Padraic Cunningham
Padraic Cunningham

Reputation: 180481

If you want to ignore certain indexes, you could use enumerate:

" ".join([str(i) for ind,i in enumerate(data[0][0:4]) if ind != 1])

Upvotes: 0

abarnert
abarnert

Reputation: 365945

If you want it to print everything from data[0][0:4] that isn't the number 2, you can do this:

print([x for x in data[0][0:4] if x != 2])

This can be extended to, e.g., not print even numbers:

print([x for x in data[0][0:4] if x % 2 != 0])

If you want to "slice around" whatever's in data[0][1], you can just concatenate the two slices around it:

print(data[0][0:1] + data[0][2:4])

This can also be extended to, e.g., remove the whole slice from [1:3] instead of just [1:2]:

print(data[0][0:1] + data[0][3:4])

Although it doesn't work as well for removing discontiguous groups (like whatever's in index 1, 3, or 8); for that, you'd probably want enumerate.

Upvotes: 1

inspectorG4dget
inspectorG4dget

Reputation: 114035

In [288]: data=[[1, 2, 3, 4, 5, 6, 7], [2, 4, 3, 6, 5]]

In [289]: for i in [0,2,3]:
   .....:     print(data[0][i], end=' ')
   .....:     
1 3 4

Upvotes: 3

Gillespie
Gillespie

Reputation: 6561

print([data[0][0]] + data[0][2:4])

Upvotes: 2

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