CODEWITHSUNDEEP
python
Beta
Beta

Reputation: 1756

Print Individual Elements of List

I've an array of this format:

val = [[1302, 303, 168, 536],
 [1424, 360, 226, 677],
 [776, 321, 194, 509],
 [1066, 276, 191, 571]]

I'm extracting first and second element of the array in the following way:

x = [col for col in list(zip(*val))[0]]
y = [col for col in list(zip(*val))[1]]

Creating an empty set:

points = set()

Creating a tuple with combination of list:

center = tuple(zip(x,y))

Appending the list in the point dataset:

points.add(center)

Finally trying to print one list at a time:

for point in points:
    print(point)

I'm getting the following result:

((1302, 303), (1424, 360), (776, 321), (1066, 276))

But I want it should print:

First, (1302, 303)

Second, (1424, 360)

and so on.

Can someone please guide me how to do it?

Thanks!

Upvotes: 0

Views: 276

Answers (3)

Austin
Austin

Reputation: 26047

You can just iterate over your original list:

for x in val:
    print(tuple(x[:2]))

Or from your points using unpacking and passing sep:

points = ((1302, 303), (1424, 360), (776, 321), (1066, 276))

print(*points, sep='\n')
# (1302, 303)
# (1424, 360)
# (776, 321) 
# (1066, 276)

Upvotes: 1

Neb
Neb

Reputation: 2280

I find this too complicated:

x = [col for col in list(zip(*val))[0]]
y = [col for col in list(zip(*val))[1]]

Instead, you could do:

x = [col[0] for col in val]
y = [col[1] for col in val]

Then, create your points data structure:

points = set([(i, j) for i, j in zip(x, y)])

Print your points:

for point in points:
    print(point)

Upvotes: 1

Devesh Kumar Singh
Devesh Kumar Singh

Reputation: 20500

Just use a double for-loop

#Iterate over the set
for point in points:
    #Iterate on each point
    for item in point:
        print(item)

This will output

(1302, 303)
(1424, 360)
(776, 321)
(1066, 276)

To print it in a single loop, you need to modify your points set to a 1-D list

val = [[1302, 303, 168, 536],
 [1424, 360, 226, 677],
 [776, 321, 194, 509],
 [1066, 276, 191, 571]]


x = [col for col in list(zip(*val))[0]]
y = [col for col in list(zip(*val))[1]]
points = set()
center = tuple(zip(x,y))
points.add(center)

#Convert set to a 1-D list
points = list(*points)

for point in points:
    print(point)

This will output

(1302, 303)
(1424, 360)
(776, 321)
(1066, 276)

Or a one-liner print without loops

val = [[1302, 303, 168, 536],
 [1424, 360, 226, 677],
 [776, 321, 194, 509],
 [1066, 276, 191, 571]]


x = [col for col in list(zip(*val))[0]]
y = [col for col in list(zip(*val))[1]]
points = set()
center = tuple(zip(x,y))
points.add(center)

#One liner print
print(*list(*points), sep='\n')

Upvotes: 1

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