CODEWITHSUNDEEP
javaandroidstringintegerandroid-edittext
James Andrew
James Andrew

Reputation: 7243

Converting a string to an integer on Android

How do I convert a string into an integer?

I have a textbox I have the user enter a number into:

EditText et = (EditText) findViewById(R.id.entry1);
String hello = et.getText().toString();

And the value is assigned to the string hello.

I want to convert it to a integer so I can get the number they typed; it will be used later on in code.

Is there a way to get the EditText to a integer? That would skip the middle man. If not, string to integer will be just fine.

Upvotes: 206

Views: 678435

Answers (14)

waleed
waleed

Reputation: 67

I have simply change this

int j = Integer.parseInt(user.replaceAll("[\\D]", ""));

into

int j = 1;

AND IT SOLVE MY PROBLEM

Upvotes: 2

user11151078
user11151078

Reputation: 51

There are five ways to convert The First Way : 

String str = " 123" ;
int i = Integer.parse(str); 
output : 123

The second way :

String str = "hello123world";
int i = Integer.parse(str.replaceAll("[\\D]" , "" ) );
output : 123

The Third Way :

String str"123";
int i = new Integer(str);
output "123

The Fourth Way : 

String str"123";
int i = Integer.valueOf(Str);
output "123

The Fifth Way :

String str"123";
int i = Integer.decode(str);
output "123

There could be other ways But that's what I remember now

Upvotes: 5

Khemraj Sharma
Khemraj Sharma

Reputation: 58934

Kotlin

There are available Extension methods to parse them into other primitive types.

Java

String num = "10";
Integer.parseInt(num );

Upvotes: 3

Joseph Chotard
Joseph Chotard

Reputation: 695

The much simpler method is to use the decode method of Integer so for example:

int helloInt = Integer.decode(hello);

Upvotes: 3

Jonathan Holloway
Jonathan Holloway

Reputation: 63662

See the Integer class and the static parseInt() method:

http://developer.android.com/reference/java/lang/Integer.html

Integer.parseInt(et.getText().toString());

You will need to catch NumberFormatException though in case of problems whilst parsing, so:

int myNum = 0;

try {
    myNum = Integer.parseInt(et.getText().toString());
} catch(NumberFormatException nfe) {
   System.out.println("Could not parse " + nfe);
}

Upvotes: 468

Ravi Makvana
Ravi Makvana

Reputation: 2902

Try this code it's really working.

int number = 0;
try {
    number = Integer.parseInt(YourEditTextName.getText().toString());
} catch(NumberFormatException e) {
   System.out.println("parse value is not valid : " + e);
}

Upvotes: 8

Abdul Rizwan
Abdul Rizwan

Reputation: 4108

You can use the following to parse a string to an integer:

int value=Integer.parseInt(textView.getText().toString());

(1) input: 12 then it will work.. because textview has taken this 12 number as "12" string.

(2) input: "abdul" then it will throw an exception that is NumberFormatException. So to solve this we need to use try catch as I have mention below:

  int tax_amount=20;
  EditText edit=(EditText)findViewById(R.id.editText1);
     try
       {

        int value=Integer.parseInt(edit.getText().toString());
        value=value+tax_amount;
        edit.setText(String.valueOf(value));// to convert integer to string 

       }catch(NumberFormatException ee){
       Log.e(ee.toString());
       }

You may also want to refer to the following link for more information: http://developer.android.com/reference/java/lang/Integer.html

Upvotes: 5

user1971876
user1971876

Reputation:

Use regular expression is best way to doing this as already mentioned by ashish sahu

public int getInt(String s){
return Integer.parseInt(s.replaceAll("[\\D]", ""));
}

Upvotes: 9

Brett Moan
Brett Moan

Reputation: 151

You can also do it one line:

int hello = Integer.parseInt(((Button)findViewById(R.id.button1)).getText().toString().replaceAll("[\\D]", ""));

Reading from order of execution

  1. grab the view using findViewById(R.id.button1)
  2. use ((Button)______) to cast the View as a Button
  3. Call .GetText() to get the text entry from Button
  4. Call .toString() to convert the Character Varying to a String
  5. Call .ReplaceAll() with "[\\D]" to replace all Non Digit Characters with "" (nothing)
  6. Call Integer.parseInt() grab and return an integer out of the Digit-only string.

Upvotes: 4

Ashish Sahu
Ashish Sahu

Reputation: 1558

Use regular expression:

String s="your1string2contain3with4number";
int i=Integer.parseInt(s.replaceAll("[\\D]", ""));

output: i=1234;

If you need first number combination then you should try below code:

String s="abc123xyz456";
int i=NumberFormat.getInstance().parse(s).intValue();

output: i=123;

Upvotes: 28

Ashish Sahu
Ashish Sahu

Reputation: 1558

Use regular expression:

int i=Integer.parseInt("hello123".replaceAll("[\\D]",""));
int j=Integer.parseInt("123hello".replaceAll("[\\D]",""));
int k=Integer.parseInt("1h2el3lo".replaceAll("[\\D]",""));

output:

i=123;
j=123;
k=123;

Upvotes: 13

Ravi
Ravi

Reputation: 35549

Best way to convert your string into int is : 

 EditText et = (EditText) findViewById(R.id.entry1);
 String hello = et.getText().toString();
 int converted=Integer.parseInt(hello);

Upvotes: 7

Tren Narek
Tren Narek

Reputation: 61

You should covert String to float. It is working.

float result = 0;
 if (TextUtils.isEmpty(et.getText().toString()) {
  return;
}

result = Float.parseFloat(et.getText().toString());

tv.setText(result);

Upvotes: 5

manuel
manuel

Reputation: 1840

int in = Integer.valueOf(et.getText().toString());
//or
int in2 = new Integer(et.getText().toString());

Upvotes: 51

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