CODEWITHSUNDEEP
javaandroid
Mahmoud Elattar
Mahmoud Elattar

Reputation: 1

EditText to integer in android

i checked this web site on how to convert from string to integer type in java(android).... one of suggestion was to use (integer.parseint) i used it and when i run my application it says my app has stopped working my code below .

 public void clickable (View view){
           EditText mytext = (EditText) findViewById(R.id.Creat);
           int number = Integer.parseInt(mytext.getText().toString());
           Toast.makeText(getApplicationContext(), number ,Toast.LENGTH_LONG).show();

   }

i cant figure out what is the problem with the code ?!

Upvotes: 0

Views: 69

Answers (3)

aneurinc
aneurinc

Reputation: 1238

There are many implementations of Toast.makeText. As you are passing an int as the second argument, the following implementation will execute:

Toast makeText(Context context, @StringRes int resId, @Duration int duration)

This implementation will throw a ResourcesNotFoundException if it cannot find a resource with the id of resId.

To output number as a String you need to convert it:

Toast.makeText(getApplicationContext(), String.valueOf(number), Toast.LENGTH_LONG).show();

Upvotes: 0

Ali
Ali

Reputation: 859

Declare EditText mytext variable as a global variable and then initialize it in Oncreate() method of your Activity. Then your clickable method looks like this:

public void clickable (View view){
       int number = Integer.parseInt(mytext.getText().toString());
       Toast.makeText(getApplicationContext(), mytext.getText().toString(), Toast.LENGTH_LONG).show();
}

Obeserve Toast.makeText() method's second argument is the resource id of the string resource to use or it can be formatted text. In your code you have passed an integer as a resource id which does not exist. So you get ResourcesNotFoundException.

Upvotes: 1

RGV
RGV

Reputation: 21

What string are you passing into the Integer.parseInt()? If it's not an integer, your program will experience a NumberFormatException. I'm not sure if that's the issue here, but I'm not sure what you're passing into the Integer.parseInt().

Upvotes: 0

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