Reputation: 4632
I am new to django ..the same question is there already but i cant understand what this error is.. i keep getting this error in the url line. pls help me to resolve this error with explanation.
views.py
def srch(request):
return render(request,'feeds/search.html')
urls.py
url(r'^search/$',views.srch,name='search')
and in html
<a href="{% url 'feeds:search' %}"> click </a>
thanks in advance for ur help ..
Upvotes: 0
Views: 590
Reputation: 19
I had the same problem and I solved it by redirecting like this:
url(r'^password-reset/$', login_views.password_reset, {'post_reset_redirect' : 'password-reset/done/'}, name='password_reset')
So, I also have the:
url(r'^password-reset/done/$', login_views.password_reset_done, name='password_reset_done')
Upvotes: 0
Reputation: 2038
you must read about URL namespace.. and also check in your project level urls.py entry of feeds
application which should be like
url(r'feeds/',include('feeds.urls',namespace='feeds'))
..
I might not be correct but I think problem is in urls.py
of your project
Upvotes: 1
Reputation: 107
Maybe you can try replacing {% url 'feeds:search' %} with {% url 'search' %}"> ?
Upvotes: 2