CODEWITHSUNDEEP
javascriptphpjqueryajaxjson
Neelabh Singh
Neelabh Singh

Reputation: 2678

How to send Json data into database using Jquery and Ajax?

I have made form of customer details form when I click the button, It send Json data to customer. But my code is not inserting data into database. I am new in web technology, please tell me where I am wrong.

my Script:

 <script>   
    $(document).ready(function(){              
            $("#btnBooking").on("click", function(){                   

                var uName = document.getElementById('userName').value;        
                var mailId = document.getElementById('addressemailId').value;           
                var mobNum = document.getElementById('userContactNumber').value;                    
                $.ajax({
                    url:"http://192.168.1.11/customerhomes/customer.php", 
                    type:"GET", 
                    dataType:"json", 
                    data:{type:"booking",Name:uName, Email:mailId, Mob_Num:mobNum}, 
                    //type: should be same in server code, otherwise code will not run
                    ContentType:"application/json", 
                    success: function(response){ 
                            alert("13");                                                 
                        }, 
                        error: function(err){ 
                        alert(JSON.stringify(err)); 
                    } 
                })              
            }); 
    });
</script>

form in html

<body>
    <div class="page-header text-center">
        <form >
            <div class="col-lg-8">                                  
                <div class="form-group">
                        <label class="col-lg-3 control-label">Name:<font style="color: red;">*</font></label>
                        <div class="col-lg-9">
                            <input type="text" class="form-control" id="userName" name="userName" placeholder="Full Name" value="">
                        </div>
                </div>


                <div class="form-group">
                    <label class="col-lg-3 control-label">Mobile:<font style="color: red;">*</font></label>
                    <div class="col-lg-9">
                        <input type="text" class="form-control" id="userContactNumber" name="userContactNumber" type="number" placeholder="" onkeypress="enableKeys(event);" maxlength="10" placeholder="9966778888">
                    </div>
                </div>

                <div class="form-group">
                        <label class="col-lg-3 control-label">Email:<font style="color: red;">*</font></label>
                        <div class="col-lg-9">                                  
                            <input type="text" class="form-control" name="addressemailId" id="addressemailId" placeholder="[email protected]" value="">
                        </div>
                </div>  
                <div class="form-group marg-bot-45">
                    <label class="col-lg-3 control-label"></label>
                    <div class="col-lg-9">

                        <a href="" class="btn btn-info"  id="btnBooking">Confirm Booking</a>
                    </div>
                </div>
            </div>
        </form>
    </div>
</body>

server code 

<?php
header('Access-Control-Allow-Origin: *');//Should work in Cross Domaim ajax Calling request
mysql_connect("localhost","root","1234");
mysql_select_db("customer_details");
if(isset($_GET['type']))
{
    if($_GET['type']=="booking"){
        $name = $_GET ['Name'];
        $mail = $_GET ['Email'];
        $mobile = $_GET ['Mob_Num'];
        $query1 = "insert into customer(cust_name, cust_mobile, cust_email) values('$name','$mail','$mobile')";
        $result1=mysql_query($query1);
    }
}
else{
    echo "Invalid format";
}

Upvotes: 1

Views: 13760

Answers (3)

Anand Patel
Anand Patel

Reputation: 3943

Use this

JavaScript Code:

<script>
        $(document).ready(function(){
            $("#btnBooking").on("click", function(e){

                // as you have used hyperlink(a tag), this prevent to redirect to another/same page
                e.preventDefault();

                // get values from textboxs  
                var uName = $('#userName').val();
                var mailId = $('#addressemailId').val();
                var mobNum = $('#userContactNumber').val();

                $.ajax({
                    url:"http://192.168.1.11/customerhomes/customer.php",
                    type:"GET",
                    dataType:"json",
                    data:{type:"booking",Name:uName, Email:mailId, Mob_Num:mobNum},
                    //type: should be same in server code, otherwise code will not run
                    ContentType:"application/json",
                    success: function(response){
                        alert(JSON.stringify(response));
                    },
                    error: function(err){
                        alert(JSON.stringify(err));
                    }
                })
            });
        });
    </script>

PHP Code

<?php
header('Access-Control-Allow-Origin: *');//Should work in Cross Domaim ajax Calling request
 mysql_connect("localhost","root","1234");
 mysql_select_db("customer_details");
if(isset($_GET['type']))
{
    $res = [];

    if($_GET['type'] =="booking"){
        $name  = $_GET ['Name'];
        $mail  = $_GET ['Email'];
        $mobile  = $_GET ['Mob_Num'];
        $query1  = "insert into customer(cust_name, cust_mobile, cust_email) values('$name','$mail','$mobile')";
        $result1 = mysql_query($query1);

        if($result1)
        {
            $res["flag"] = true;
            $res["message"] = "Data Inserted Successfully";
        }
        else
        {
            $res["flag"] = false;
            $res["message"] = "Oppes Errors";
        }

    }
}
else{
    $res["flag"] = false;
    $res["message"] = "Invalid format";
}

    echo json_encode($res);
?>

If data is inserted successfully it return true flag with message, otherwise false flag with message

Upvotes: 1

archish
archish

Reputation: 142

try this it might help you.

in your ajax function:

1st change : ContentType:"application/json" to contentType: "application/json; charset=utf-8"

2nd

in data:{type:"booking",Name:uName, Email:mailId, Mob_Num:mobNum} change to data:{type1:"booking",Name:uName, Email:mailId, Mob_Num:mobNum}. see you set type as GET in ajax function so i am thinking that "type" is reserved word, so it might not work. and also check your url where you are sending ajax request if it is correct or not bcoz you are using ip address.

in your server code i am seeing typo. there is space between

$_GET ['name'], $_GET ['Email'], $_GET ['Mob_Num'].

there should be no space so change it to this,

$_GET['name']

$_GET['Email']

$_GET['Mob_Num']

Upvotes: 0

scgough
scgough

Reputation: 5252

I would first of all change the "GET" to a "POST" on both the ajax call and the receiving PHP page on the server.

Secondly, I'd check that the values are actually being passed to the PHP page by using echo to output each of them on the PHP side. That way you'll know at least the values are coming through.

JavaScript:

var uName = $('#userName').val();        
var mailId = $('#addressemailId').val();           
var mobNum = $('userContactNumber').val();                    
$.ajax({
    url:"http://192.168.1.11/service4homes/customer.php", 
    type:"POST", 
    data:{type:"booking",Name:uName, Email:mailId, Mob_Num:mobNum}, 
    complete: function(response){ 
        var test = $.parseHTML(response);
        alert(test);
    }
 });

PHP Code:

echo $_POST["type"];
echo $_POST["Name"];
//etc...

Upvotes: 0

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