CODEWITHSUNDEEP
java
wrivera24
wrivera24

Reputation: 21

Unexpected type error in hangman class

I am coding a hangman class and have a little problem with an unexpected type error. This error is in the this.hidden.charAt(i) = this.original.charAt(i);. Any help will be appreciated.

public class HangmanClass {


        private ArrayList<String> words = new ArrayList();
        private String word;
        private final static char HIDECHAR = '*';


        private String original;
        private String hidden;

        public void HangmanWord(String original){
            this.original = original;
            this.hidden = this.hideWord();
        }

        public String getWord() {

            words.add("greetings");
            words.add("cheese");
            words.add("making");
            words.add("juvenile");
            words.add("car");
            word = words.get(new Random().nextInt(words.size()));
            return word;

        }

        private String hideWord() {
            StringBuilder sb = new StringBuilder();
            for (int i = 0; i < word.length(); i++) {
                sb.append(HIDECHAR);
            }
            return sb.toString();
        }

        public boolean checkInput(char input){
            boolean found = false;
            for (int i = 0; i < this.original.length(); i++) {
                if (this.original.charAt(i) == input) {
                    found = true;
                    this.hidden.charAt(i) = this.original.charAt(i);  
                }
            }
              return found;      

        }


    };

Upvotes: 0

Views: 55

Answers (2)

nitishagar
nitishagar

Reputation: 9413

The charAt(int) in String cannot be used to assign values. You can use something like:

this.hidden.setCharAt(i, this.original.charAt(i));

The above works on StringBuilder, as String is an immutable class in Java. In String case you can use something like (generates a new String every time):

this.hidden = this.hidden.substring(0,i) + this.original.charAt(i) + this.hidden.substring(i);

Upvotes: 2

M A
M A

Reputation: 72884

String.charAt(int) cannot be used on the left-hand side of an assignment statement. And you cannot change / mutate Strings in Java.

Use a StringBuilder.setCharAt(int index, char ch) instead.

Upvotes: 2

Related Questions