CODEWITHSUNDEEP
python
Robert Bedrosian
Robert Bedrosian

Reputation: 47

I am getting in <string>' requires string as left operand, not tuple

s = raw_input("string: ")

if ("a", "e", "i", "o", "u") in s:
    print s.count("a", "e", "i", "o", "u")
else:
    print ("No vowels")

this is my code, essentially i want someone to type in a string and for this program to count the amount of vowels. Why doesnt this work?

Upvotes: 1

Views: 14027

Answers (6)

user1804599
user1804599

Reputation:

Check whether it's a subset:

if set("aeiou") <= set(s):
    ...

Upvotes: 2

PaulMcG
PaulMcG

Reputation: 63709

Here is a snippet using Python's built-in sum, which relies on Python's equivalence of True and 1:

>>> s = "sldkjfwoqpwefjsfueiof"
>>> num_vowels = sum(c in "aeiou" for c in s.lower())
>>> print num_vowels
6

For every character in s, evaluate whether it is in "aeiou" or not. If it is, this evaluates to True, equivalent to the value 1. Characters not in "aeiou" evaluate to False, equivalent to 0. sum adds these all up, the result will tell you how many characters in the input string satisfy the vowel condition. (Don't forget to convert the input string to lower case as shown by calling .lower(), else you will accidentally skip over vowels that are capitalized.)

Upvotes: 1

dragon2fly
dragon2fly

Reputation: 2419

Your code checks if a tuple ("a", "e", "i", "o", "u") is inside string s which of course is not existed. If you need keep track of what vowel has been repeated how many times, you should do like this:

In[22]: s = 'aiuo hohoho'
In[23]: vowel_count = {i:s.count(i) for i in 'aiueo'}
In[24]: vowel_count
Out[24]: {'a': 1, 'e': 0, 'i': 1, 'o': 4, 'u': 1}

It gives you a dict of vowel:counts, so you can get the count of any vowel like this:

In[25]: vowel_count['o']
Out[25]: 4

Upvotes: 2

Adam Hughes
Adam Hughes

Reputation: 16309

I bet it's trying to see if the tuple, ('a','e'...) is in the string, not the items individually. Iterate:

count = 0
for letter in 'aeiou':
   if letter in s:
       count += s.count(letter)
print count

Upvotes: 3

Stephen Lin
Stephen Lin

Reputation: 4912

You can do it in this way. Every element in the final list is the count of vowels you want.

#!/usr/bin/python
# -*- coding: utf-8 -*-
# Take this for an example
a = 'aeiouaeioujjj'
print [a.count(item) for item in 'aeiou']

OUTPUT:

[2, 2, 2, 2, 2]

Upvotes: 1

lqhcpsgbl
lqhcpsgbl

Reputation: 3782

Or you can use a dict to remember the count of vowels:

s = raw_input("string: ")

aeiou_dict = {'a':0,'e':0,'i':0,'o':0,'u':0}

for char in s:
   if char in 'aeiou':
      aeiou_dict[char] += 1
   else:
      pass

print aeiou_dict

Upvotes: 1

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