Reputation: 6512
In emacs there is buffer-file-name that gives the full path to a file. But is there a way to get only the directory of the file loaded in the current buffer?
Upvotes: 43
Views: 26885
Reputation: 46
You can use the command M-x pwd
to see the value of default-directory
in the current buffer.
Each buffer has a default directory, stored in the buffer-local variable default-directory
. Whenever Emacs reads a file name using the minibuffer, it usually inserts the default directory into the minibuffer as the initial contents. When you visit a file, Emacs sets default-directory
in the visiting buffer to the directory of its file.
https://www.gnu.org/software/emacs/manual/html_node/emacs/File-Names.html
Upvotes: 0
Reputation: 839
Sometimes default-directory
for the current buffer may be set to something other than the current directory of the file the buffer is currently visiting, in which case the solution above wouldn't give what the asker was looking for.
In such cases, you can use the file-name-directory
method, like so: (file-name-directory buffer-file-name)
Here is a link to the docs:
http://www.gnu.org/software/emacs/manual/html_node/elisp/File-Name-Components.html
Upvotes: 56
Reputation: 20362
You can use the default-directory
variable.
Documentation: Name of default directory of current buffer. Should end with slash. To interactively change the default directory, use command `cd'.
Note that expand-file-name
will use default-directory
by default, so sometimes
you don't even need to mention it.
Upvotes: 32