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c++templatesfunctionmember
Maxime
Maxime

Reputation: 81

Specialization of a member of a template class for a template class parameter type

I have a templated class Matrix. I want to specialize a function for the type complex, where T can be anything. I have tried this :

  6 template <typename T>
  7 class Matrix {
  8       public :
  9             static void f();
 10 };          
 11 template<typename T> void Matrix<T>::f() { cout << "generic" << endl; }
 12 template<> void Matrix<double>::f() { cout << "double" << endl; }
 13 template<typename T> void Matrix<std::complex<T> >::f() { cout << "complex" << endl; }

Line 13 does not compile. How can I do that ?

Upvotes: 5

Views: 673

Answers (3)

Kirill V. Lyadvinsky
Kirill V. Lyadvinsky

Reputation: 99535

In lines 11 and 12 you have declaration of explicit specialization for a member of a class template which is allowed by C++ Standard 14.7/3 (14.5.2/2 contains a good example too). In line 13 you are trying to partially specialize a class template and that is not allowed in this form (this is partial specialization because you don't know the whole type std::complex<T> because it is still depends on T). You should partially specialize the whole class.

Upvotes: 3

Maxime
Maxime

Reputation: 81

In fact, I found a clever way to do it through Boost. Since I don't want my library to be dependant on Boost, here is the code :

template <class T, T val> struct integral_constant
{
      typedef integral_constant<T, val> type;
      typedef T value_type;
      static const T value = val;
};    
typedef integral_constant<bool, true>  true_type;
typedef integral_constant<bool, false> false_type;
template <typename T> struct is_complex : false_type{};
template <typename T> struct is_complex<std::complex<T> > : true_type{};

template <typename T>
class Matrix {
      public :
            static void f() { f_( typename is_complex<T>::type() ); }
      private :
            static void f_( true_type ) { cout << "generic complex" << endl; }
            static void f_( false_type ) { cout << "generic real" << endl; }
};          
template<> void Matrix<double>::f() { cout << "double" << endl; }

This way, I can use function overloading and template to achievement my goal.

Upvotes: 1

Phil Miller
Phil Miller

Reputation: 38108

As describe in the linked answer, what you'll need to do is specialize the entire class, rather than the simple function:

#include <iostream>
#include <complex>
using namespace std;

template <typename T>
class Matrix {
public :
    static void f();
};

template<typename T> void Matrix<T>::f() { cout << "generic" << endl; }
template<> void Matrix<double>::f() { cout << "double" << endl; }

template <typename T>
class Matrix<std::complex<T> > {
public:
    static void f() { cout << "complex" << endl; }
};

int main(void) {
  Matrix<complex<double> >::f();
  return 0;
}

Upvotes: 0

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