CODEWITHSUNDEEP
pythonstring
iqueqiorio
iqueqiorio

Reputation: 1187

python - remove text of string

I have a string that looks like this

name = '1/23/20151'

And now I want to remove just the trailing 1, at the end of 2015. So that it becomes 

1/23/2015

So i tried this

sep = '2015'
name = name.split(sep, 1)[0]

but this removes the 2015 also, I want the 2015 to stay, how could I do this.

Thanks for the help in advance.

EDIT

Sorry I didn't fully explain the problem I have two strings the one previously mentioned and a noraml date '1/22/2015' and I loop through and only want to remove this extra character if it is there which is why name = name[:-1] doesn't work.

Upvotes: 1

Views: 107

Answers (3)

deweyredman
deweyredman

Reputation: 1450

just do this 

name = name[:-1]

That should do it.

If you only want to remove the fifth digit after the year, I'd do this:

name = name.split('/')
name = '/'.join([name[0],name[1],name[2][:4]])

Upvotes: 2

taesu
taesu

Reputation: 4570

name = name.rstrip('1')

will only remove trailing '1'

name = '1/23/20151'
name = name.rstrip('1') # 1/23/2015
'1/23/2015'.rstrip('1') # 1/23/2015

Upvotes: 4

N1B4
N1B4

Reputation: 3453

List slicing can easily accomplish this:

>>> name[:-1]
>>> '1/23/2015'

Upvotes: 1

Related Questions