CODEWITHSUNDEEP
pythonpython-2.7
Dexter
Dexter

Reputation: 23

Removing a certain part of a string?

Not sure how to do this. I have a string that I need the first part of it gone. When print(result.text) runs it prints "@PERSONSTWITTER their message" I need to remove the first part "@PERSONSTWITTER".

At first I had it remove everything from the @. I ran into a problem, the first is that the person username could be any amount of letters. (@PERSONSTWITTER2, @PERSONSTWITTER12, etc) they don't have the same amount of characters. Now I'm not sure what to do. Any help would be great!

So all I need is to isolate "their message" and not the username.

for s in twt:
    sn = s.user.screen_name
    m = "@%s MESSAGE" % (sn)
    s = api.update_status(m, s.id)
    #time.sleep(5)

for result in twt:
    print(result.text)

Upvotes: 0

Views: 72

Answers (4)

Boki_LV
Boki_LV

Reputation: 21

s = "@PERSONSTWITTER their message"
split_s = s.split(' ')
message = ' '.join( split_s[1:] )

Upvotes: 0

Moinuddin Quadri
Moinuddin Quadri

Reputation: 48057

You may filter the words starting with @ using string.startswith as:

>>> s = "@PERSONSTWITTER their message. @ANOTHERWRITER their another message."

>>> ' '.join(word for word in s.split() if not word.startswith('@'))
'their message. their another message.'

Here I'm firstly splitting your sentence into words, filtering the words not starting with @, and then joining back again.

Upvotes: 1

Joe Iddon
Joe Iddon

Reputation: 20414

Use the .split() method to convert the string into a list of strings formed from splitting the original at (by default) spaces.

Then use the .join method to join all the elements from index 1 on wards in the list together, separated again by a space.

s = "@PERSONSTWITTER their message"
' '.join(s.split()[1:])
# --> 'their message'

An alternative approach would be to just index the first space and slice from then on wards:

s = "@PERSONSTWITTER their message"
s[s.index(' ')+1:]
# --> 'their message'

Note that we had to add 1 to the index because strings are zero-based

Upvotes: 0

Ajax1234
Ajax1234

Reputation: 71451

You can use regular expressions:

import re
s = "@PERSONSTWITTER their message" 
new_s = re.sub('^\S+', '', s)[1:]

Output:

'their message'

Upvotes: 1

Related Questions