CODEWITHSUNDEEP
java
bgeveritt
bgeveritt

Reputation: 303

Get text after last number in alphanumeric string

I have the following string:

"Hard120109Missing or invalid shipper phone number"

How would I use Java to get the following:

"Missing or invalid shipper phone number"

Basically, I want to only retrieve the text after the last occurrence of a number.

Upvotes: 1

Views: 336

Answers (4)

EDToaster
EDToaster

Reputation: 3180

String[] arr = yourString.split("[0-9]+");

String newString = arr[1]; //get string after first number

First, split your string by any digits, and then get your string from array

For different amounts of numbers:

String[] arr = yourString.split("[0-9]+", 2);

StringBuilder sb = new StringBuilder();

if (arr.length <= 1) 
    throw new RuntimeException("Invalid String");

for (int i = 1; i < arr.length; i++)
     sb.append(arr[i]);
String newString = sb.toString();

Heres another way:

String newString  = "";
try{
    yourString.split("[0-9]+", 2)[1];
} catch(ArrayIndexOutOfBoundsException e){} //leaves newString as ""

Upvotes: 3

Kapparino
Kapparino

Reputation: 988

String str = "Hard120109Missing or invalid shipper phone number";
String newStr = "";
for (int i = str.length() - 1; i >= 0; i--) {
    char ch = str.charAt(i);
    if (Character.isDigit(ch)) break;

    newStr =  ch + newStr;
}

Upvotes: 1

Neo
Neo

Reputation: 4880

You can use split to get the last part of the String

String msg = "Hard120109Missing or invalid shipper phone number";
String val[] = msg.split("\\d+");
if (val.length > 1) {
  System.out.println("Message= " + val[1]);
}

Output

Message= Missing or invalid shipper phone number

Upvotes: 1

russellsayshi
russellsayshi

Reputation: 2569

You could always loop (assume this is its own helper method):

for(int i = str.length()-1; i >= 0; i--) {
    char c = str.charAt(i);
    if(c >= '0' && c <= '9') {
        return str.substring(i+1);
    }
}
return "";

Upvotes: 0

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