CODEWITHSUNDEEP
java
user4833678
user4833678

Reputation:

Outputting that number along with a single character of the repeating sequence

folks! I've been practicing different tasks on Java and this one has been taking me a while to figure out. A user has to enter only String of letters and for example, if a user enters smth like wwwzddfffff the ouput should be 3w1z2d5f or, another example, kklllk and the ouput should be 3k3l. The method runLength() takes the occurrence of each repeating character and outputs that number along with a single character of the repeating sequence.
What I am getting is:

Enter any String: 
wwwwzzzz
7z




    import java.util.Scanner;

public class RunLength {

    public static void main(String[] args)
    {
        Scanner kbd = new Scanner(System.in);
        System.out.println("Enter any String: ");
        String word = kbd.nextLine();
        String result = runLength(word);
        System.out.println(result);
    }

    public static String runLength(String word)
    {
        char[] chars = word.toCharArray();
        char firstChar = chars[0];
        char temp = 0;
        int count = 0;
        String result = "";

        for(int i = 1; i < chars.length; i++)
        {

            if(firstChar == chars[i])
            {
                temp = firstChar;
                count++;
                result = count+""+temp;
            }

            else if(firstChar != chars[i])
            {
                temp = chars[i];
                count++;
                result = count+""+temp;
            }
        }

        return result;
    }

}

Upvotes: 2

Views: 640

Answers (3)

xrisk
xrisk

Reputation: 3898

class test
{


public static void main(String args[])
    {
        System.out.println(runlength("aaabbc"));
    }
static String runlength(String s)
{
    String current="";
    int count = 1;
    char[] c = s.toCharArray();
    for(int i = 1; i < c.length; i++)
    {
        if (c[i]==c[i-1])
            count++;

        else 
        {
            current = current + count + Character.toString(c[i-1]);
            count = 1;
        }
    }
    return current + count + Character.toString(c[c.length-1]);
}
}

Upvotes: 1

Saurabh Jhunjhunwala
Saurabh Jhunjhunwala

Reputation: 2922

Would like you to rewrite runLength method.

public static Map runLength(String word) {
        char[] chars = word.toCharArray();
        char firstChar = chars[0];
        Map charMap = new HashMap();

        for(int i = 0; i < chars.length; i++) {
            if(charMap.contains(chars[i])
                charMap.put(chars[i],++charMap.get(chars[i]));
            else
               charMap.put(chars[i],1);
        }
        return charMap;
    }

// in the main method

Map myMap = runLength(word);

for (Entry entry : myMap.entrySet()) {
    System.out.print(myMap.get(entry.getKey())+entry.getKey());
}

Upvotes: 0

Tot Zam
Tot Zam

Reputation: 8756

Sounds like a HashMap will solve your problem. Try: 

 Map<Character, Integer> counter = new HashMap<Character, Integer>();
    char[] chars = word.toCharArray();
    for(char c: chars){
        if(counter.containsKey(c)){
            counter.put(c, c.get(c) ++);
        }
        else{
            counter.put(c, 1);
        }
    }

Then to print:

StringBuilder builder = new StringBuilder();
for (Character c : counter.keySet()) {
        builder.append(c);
        builder.append(counter.get(c));
}

return builder.toString();

Upvotes: 0

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