CODEWITHSUNDEEP
java
user5391020
user5391020

Reputation:

Printing a number next to each String

I have a method that prints out the elements of a String array that are not null. Desired output:

1. cook
2. chef
3. baker
4. butcher
5. distiller

Output getting:

1. cook
3. chef
4. baker
7. butcher
9. distiller

The numbers aren't consecutive like they are in the first example. Obviously it's because it's only printing 'i' when 'i' is not null. Is there anyway I can make it look like the first example? I've tried different solutions but none of them seem to work.

public class Main {

public void testMethod() {
    String myArray[] = new String [] { "cook", null, "chef", "baker", null, null, "butcher", null, "distiller" };
    for (int i = 0; i < myArray.length; i++) {
        if (myArray[i] != null) 
            System.out.println((i + 1) + ". " + myArray[i]);
    }   
}

public static void main(String[] args) {
    Main main = new Main();
    main.testMethod();
}
}

Upvotes: 2

Views: 61

Answers (6)

Siva Kumar
Siva Kumar

Reputation: 2006

Please try this.

public class Main {

    public void testMethod() {
        String myArray[] = new String [] { "cook", null, "chef", "baker", null, null, "butcher", null, "distiller" };

        int count = 0;

        for (int i = 0; i < myArray.length; i++) {
            if (myArray[i] != null) 
                System.out.println(((count++) + 1) + ". " + myArray[i]);
        }   
    }

    public static void main(String[] args) {
        Main main = new Main();
        main.testMethod();
    }
}

Upvotes: 0

Ankur Singhal
Ankur Singhal

Reputation: 26067

Have one more variable to count for non-null values

public void testMethod() {
        String myArray[] = new String[] { "cook", null, "chef", "baker", null,
                null, "butcher", null, "distiller" };
        int j=0;
        for (int i = 0; i < myArray.length; i++) {
            if (myArray[i] != null){
                System.out.println((j + 1) + ". " + myArray[i]);
                j++;
            }
        }
    }

output

1. cook
2. chef
3. baker
4. butcher
5. distiller

Upvotes: 0

Harish Ved
Harish Ved

Reputation: 570

You will need a new integer variable for counting. Try this -

public class Main {
    public void testMethod() {
        int iter = 1;
        String myArray[] = new String [] { "cook", null, "chef", "baker", null, null, "butcher", null, "distiller" };
        for (int i = 0; i < myArray.length; i++) {
            if (myArray[i] != null) { 
                System.out.println((iter++) + ". " + myArray[i]);
            }
        }   
    }

    public static void main(String[] args) {
        Main main = new Main();
        main.testMethod();
    }
}

Upvotes: 0

Ori Lentz
Ori Lentz

Reputation: 3688

Yes, simply keep a counter of how many you've printed, not just the indices:

public void testMethod() {
    String myArray[] = new String [] { "cook", null, "chef", "baker", null, null, "butcher", null, "distiller" };
    for (int i = 0, count = 0; i < myArray.length; i++) {
        if (myArray[i] != null) 
            System.out.println((++count) + ". " + myArray[i]);
    }   
}

Upvotes: 0

Amila
Amila

Reputation: 5213

Just keep a counter:

public void testMethod() {
    String myArray[] = new String [] { "cook", null, "chef", "baker", null, null, "butcher", null, "distiller" };
    int j = 0;
    for (int i = 0; i < myArray.length; i++) {
        if (myArray[i] != null)  {
            System.out.println(++j + ". " + myArray[i]);
        }
    }

}

Upvotes: 4

Eran
Eran

Reputation: 393831

Since you can't use i as a counter, you'll need a separate counter :

public void testMethod() {
    String myArray[] = new String [] { "cook", null, "chef", "baker", null, null, "butcher", null, "distiller" };
    int counter = 1;
    for (int i = 0; i < myArray.length; i++) {
        if (myArray[i] != null) 
            System.out.println((counter++) + ". " + myArray[i]);
    }   
}

Upvotes: 1

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